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2 years ago

For the following example, list the given and unknown information (including gratis or moles)

Chemistry

1 answer:

Setler79 [48]2 years ago

6 0

Answer:

9.6 moles O2

Explanation:

I'll assume it is 345 grams, not gratis, of water. Hydrogen's molar mass is 1.01, not 101.

The molar mass of water is 18.0 grams/mole.

Therefore: (345g)/(18.0 g/mole) = 19.17 or 19.2 moles water (3 sig figs).

The balanced equation states that: 2H20 ⇒ 2H2 +02

It promises that we'll get 1 mole of oxygen for every 2 moles of H2O, a molar ratio of 1/2.

get (1 mole O2/2 moles H2O)*(19.2 moles H2O) or 9.6 moles O2

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Read the following summary, which describes a body process. Then, answer the question.

Maksim231197 [3]

Answer:

Respiritation

Explanation:

Its Respiration because the process of breathing is known as respiration and also read the paragraph hhhhhhhhhhhhhhhhhhhhhhhh

7 0

2 years ago

which change in the temperature of the one gram sample of water would cause the greatest increase in average kinetic energy of i

LenaWriter [7]

Maybe about in the 50ths

8 0

3 years ago

Why is ginger used in food preservation

Vaselesa [24]

Spices like ginger are significantly used in preservatives because they have antimicrobial properties in their chemical compounds. They also have antioxidant properties that allow food to be preserved.

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3 years ago

Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?

chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234 would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now we start with 150 grams of Thorium-234

$150 \times \frac{1}{2}=24.1$

$75 \times \frac{1}{2} =48.2$

$34.5 \times \frac{1}{2} =72.3$

$17.25 \times \frac{1}{2} =96.4$

$8.625\times \frac{1}{2} =120.5$

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

$A=A_{0} \cdot \frac{1}{2^{n}}$

Where

$A_0$ is the initial sample amount

n = the number of half-lives that pass in a given period of time.

7 0

3 years ago

A package contains 1.33 lb of ground round. If it contains 29% fat, how many grams of fat are in the ground round? The book is s

Effectus [21]

Answer:

To obtain the grams of fat that the ground round has, knowing that it weighs 1.33 pounds we must pass this value to grams. Since 1 pound equals 453.59 grams, 1.33 pounds equals 603.27 (453.59 x 1.33).

Now, to obtain 29 percent of 603.27, we must make the following calculation: 603.27 / 100 x 29, which gives a total of 174.94 grams.

In this way, your reasoning is correct and it is probably a mistake in the book.

6 0

3 years ago