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kompoz [17]
2 years ago
7

Does density of water depend on the amount of water present ?

Chemistry
1 answer:
Nitella [24]2 years ago
7 0
<span>No, the denisty of any substance/liquid is always constant, no matter what the volume or mass is. Once the mass g/ volume mL is taken into consideration, the effect of the ammount of liquid given is canceled out. Thus, no matter what your sample is, the density of water will always be 1 g/mL</span>
You might be interested in
A metal weighing 7.101 g is placed in a graduated cylinder containing 33.0 mL of water. The water level rose to the 37.4 mL mark
musickatia [10]
Volume of the metal = change in volume reading
Volume = 37.4 - 33
Volume = 4.4 ml

Density = mass / volume
Density = 7.101 / 4.4
Density = 1.61 g/ml
7 0
3 years ago
In a chemical reaction, the difference between the potential energy of the products of the potential energy of the reactants is
natka813 [3]
In a chemical reaction, the difference between the potential energy of the products and the potential energy of the reactants is equal to the heat of the reaction<span>. This is, the net energy released or absorbed (change) during a chemical reaction is the sum of the potential energy of the products less the sum of the potential energy of the reactants.</span>
3 0
3 years ago
The mole fraction of a non-electrolyte (MM 40.0 g/mol) in a saturated aqueous solution is 0.310. What is the molality of the sol
jeka57 [31]

<u>Answer:</u> The molality of non-electrolyte is 24.69 m

<u>Explanation:</u>

We are given:

Mole fraction of saturated aqueous solution = 0.310

This means that 0.310 moles of non-electrolyte is present.

Moles of water (solvent) = 1 - 0.310 = 0.690 moles

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of water = 0.690 moles

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

0.690mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.690mol\times 18g/mol)=12.42g

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{n_{solute}\times 1000}{W_{solvent}\text{ (in grams)}}

Where,

n_{solute} = Moles of solute (non-electrolyte) = 0.310 moles

W_{solvent} = Mass of solvent (water) = 12.42 g

Putting values in above equation, we get:

\text{Molality of non-electrolyte}=\frac{0.310\times 1000}{12.42}\\\\\text{Molality of non-electrolyte}=24.96m

Hence, the molality of non-electrolyte is 24.69 m

4 0
2 years ago
In the chemical reaction, how many grams of nitrogen are needed to completely react with 24.3 grams of hydrogen
vlabodo [156]

Answer:

112.540 gram of N2

Explanation:

From the balanced chemical equation

N2+3H2----->2NH3

It means that 1 mole of Nitrogen needs 3 moles of hydrogen

In term of mass,we can say that

6.048 gram of H2 needs 28.01 gram of N2

or, 1 gram of H2 needs (28.01/6.048) gram of N2

and 24.3gram of H2 needs (24.3*28.01/6.048) gram of N2

=112.540 gram of N2

5 0
3 years ago
Please DO NOT ANSWER if you don't know and don't copy and paste from the internet
Nookie1986 [14]

I think so the answer would be Ionic Bonding

Im not sure

3 0
2 years ago
Read 2 more answers
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