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Crazy boy [7]
4 years ago
15

Reducing the emissions of which gas will lead to reducing the greenhouse effect? A) oxygen B) nitrogen C) argon D) carbon dioxid

e
Chemistry
2 answers:
professor190 [17]4 years ago
5 0
Ten Ways to Reduce Greenhouse Gases. Burning fossil fuels such as natural gas, coal, oil and gasoline raises the level of carbon dioxide<span> in the atmosphere, and</span>carbon dioxide<span> is a major contributor to the greenhouse effect and global warming.

Source -->https://www.google.com/search?q=Reducing+the+emissions+of+which+gas+will+lead+to+reducing+the+greenh...<--

</span>Can you help me? <span>brainly.com/question/3131429
</span>
Lapatulllka [165]4 years ago
3 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Green house gases are defined as the gases that absorb heat and also emit radiant heat with infrared radiation. These gases contributes to the green house effect. The heat radiated from these gases get trapped in the Earth atmosphere and it then results in the rise of temperature of the Earth surface.

There are 4 main gases that are known as green house gases. These are carbon dioxide (CO_2), methane (CH_4), nitrous oxide (N_2O) and ozone (O_3). These gases also include chlorofluorocarbons also known as CFCs.

The reduction of any these gases will result in the reduction of greenhouse gases.

Thus, the correct answer is Option D.

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One central them of Jesus' message was the kingdom of _______?
Harrizon [31]

One central them of Jesus' message was the kingdom of God

<h3>What is the gospel of Jesus?</h3>

The gospel of the Lord Jesus Christ is the ministration of God's words to sinners to repent so they can inherit the kingdom of God

The book of John says: For God so love the world that he gave his only begotten son to the world that whosoever believeth in him shall not perish but have an everlasting life

In conclusion, One major purpose of Jesus' message to humanity was to preach the gospel of the kingdom of God

Learn more about the gospel of Jesus Christ:

brainly.com/question/13540319

#SPJ1

6 0
2 years ago
The specific branch of chemistry that focuses on molecules such as salts and water that constitute non-living matter, but are st
Soloha48 [4]

Answer: Inorganic chemistry

Explanation:

Inorganic chemistry can be defined as the branch of chemistry which studies the behavior of the inorganic compounds. Inorganic compounds are those compounds which lack carbon hydrogen bonding. The carbon monoxide, carbon dioxide, sodium chloride and water are the examples of inorganic compounds. This branch also studies the effect of these chemical compounds on the living things. The water and salts are chemicals which regulate the chemical and physiological reactions in the body.

5 0
3 years ago
How many moles are in 3.2x10^23 atoms of francium?
andrew11 [14]

Answer:

i do not know i think the answer is 23

Explanation:

6 0
3 years ago
4.07 x 10-17<br> (5.6 x 10") (5.8 x 105)
Andrej [43]
4.07 x 10-17 = 23.7
(5.6 x 10”) (5.8 x 105)= log(100)
log(7)
Hope this helped
3 0
3 years ago
Given the Henry’s law constant for O2(4.34*109Pa) at 25° C, calculate the molar concentration of oxygen in air-saturated and O2s
Flauer [41]

This is an incomplete question, here is a complete question.

The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.

Answer : The molar concentration of oxygen is, 2.67\times 10^2mol/L

Explanation :

As we know that,

C_{O_2}=k_H\times p_{O_2}

where,

C_{O_2} = molar solubility of O_2 = ?

p_{O_2} = partial pressure of O_2 = 0.2 atm  = 1.97×10⁻⁶ Pa

k_H = Henry's law constant  = 4.34 × 10⁹ g/L.Pa

Now put all the given values in the above formula, we get:

C_{O_2}=(4.34\times 10^9g/L.Pa)\times (1.97\times 10^{-6}Pa)

C_{O_2}=8.55\times 10^3g/L

Now we have to molar concentration of oxygen.

Molar concentration of oxygen = \frac{8.55\times 10^3g/L}{32g/mol}=2.67\times 10^2mol/L

Therefore, the molar concentration of oxygen is, 2.67\times 10^2mol/L

8 0
3 years ago
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