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Crazy boy [7]
3 years ago
15

Reducing the emissions of which gas will lead to reducing the greenhouse effect? A) oxygen B) nitrogen C) argon D) carbon dioxid

e
Chemistry
2 answers:
professor190 [17]3 years ago
5 0
Ten Ways to Reduce Greenhouse Gases. Burning fossil fuels such as natural gas, coal, oil and gasoline raises the level of carbon dioxide<span> in the atmosphere, and</span>carbon dioxide<span> is a major contributor to the greenhouse effect and global warming.

Source -->https://www.google.com/search?q=Reducing+the+emissions+of+which+gas+will+lead+to+reducing+the+greenh...<--

</span>Can you help me? <span>brainly.com/question/3131429
</span>
Lapatulllka [165]3 years ago
3 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Green house gases are defined as the gases that absorb heat and also emit radiant heat with infrared radiation. These gases contributes to the green house effect. The heat radiated from these gases get trapped in the Earth atmosphere and it then results in the rise of temperature of the Earth surface.

There are 4 main gases that are known as green house gases. These are carbon dioxide (CO_2), methane (CH_4), nitrous oxide (N_2O) and ozone (O_3). These gases also include chlorofluorocarbons also known as CFCs.

The reduction of any these gases will result in the reduction of greenhouse gases.

Thus, the correct answer is Option D.

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How many kilograms of water must be added to 6.07 grams of oxalic acid (H2C2O4) to make a 0.025 m solution?
uranmaximum [27]
This dilution problem uses the equation
M
a
V
a
=
M
b
V
b

M
a
= 6.77M - the initial molarity (concentration)
V
a
= 15.00 mL - the initial volume
M
b
= 1.50 M - the desired molarity (concentration)
V
b
= (15.00 + x mL) - the volume of the desired solution
(6.77 M) (15.00 mL) = (1.50 M)(15.00 mL + x )
101.55 M mL= 22.5 M mL + 1.50x M
101.55 M mL - 22.5 M mL = 1.50x M
79.05 M mL = 1.50 M
79.05 M mL / 1.50 M = x
52.7 mL = x
59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M.
I hope this was helpful.
4 0
2 years ago
What is the pH of a 0.100 M HI solution? Is that neutral, acidic, or basic? acidic What is the pOH of a 0.100 M HI solution? Is
inessss [21]

<u>Answer:</u> The pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

<u>Explanation:</u>

There are three types of solution: acidic, basic and neutral

To determine the type of solution, we look at the pH values.

  • The pH range of acidic solution is 0 to 6.9
  • The pH range of basic solution is 7.1 to 14
  • The pH of neutral solution is 7.

We are given:

Concentration of HI = 0.100 M

1 mole of HI produces 1 mole of hydrogen ions and 1 mole of iodide ions

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=0.100M

Putting values in above equation, we get:

pH=-\log(0.100)\\\\pH=1

To calculate the pOH of the solution, we use the equation:

pH + pOH = 14

pOH=14-1=13

Hence, the pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

4 0
3 years ago
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