Consider these equations: 2S(s)+3O2(g)→2SO3(g) , ΔH=−792kJ 2S(s)+2O2(g)→2SO2(g) , ΔH=−594kJ 2SO2(g)+O2(g)→2SO3(g) , ΔH=? What is
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Answer:
The answer is "Option B"
Explanation:
From the query, the following knowledge is derived:
Yield in percentage = 47%
Performance of theory = 4860 g
Actual yield Rate =?
The percentage return is defined simply by the ratio between both the real return as well as the conceptual return multiplied by the 100. It's also represented as numerically:
Now We can obtain the percent yield as followed using the above formula:
The value of the Actual yield Rate =
The Actual yield Rate= 2284.2 g.