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Oliga [24]
2 years ago
15

Consider these equations: 2S(s)+3O2(g)→2SO3(g) , ΔH=−792kJ 2S(s)+2O2(g)→2SO2(g) , ΔH=−594kJ 2SO2(g)+O2(g)→2SO3(g) , ΔH=? What is

the missing ΔH ? −294kJ −198kJ +198kJ +294kJ
Chemistry
1 answer:
Elenna [48]2 years ago
6 0

Hess law can help us to obtain the enthalpy of a series of reactions by summation. The missing enthalpy of this reaction is −198kJ.

<h3>What is  Hess law?</h3>

According to the Hess law of constant heat summation, the enthalpy of a sequence of reactions can be obtained as the sum of the enthalpies of all the reactions.

Now looking at all the reavtion written here in order to obtain the missing enthalpy, we conclude that the missing enthalpy is −198kJ.

Learn more about enthalpy: brainly.com/question/3393755

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Answer:

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Explanation:

First, find the mass of empirical formula, CH. 12.01 g/mol is for carbon, and 1.008 g/mol is for hydrogen. 12.01+1.008=13.018 G/mol CH. Divide 78.110 G/mol by 13.018 g/mol. You get approximately 6. Multiply that by the subscript of each element. 6(CH)=

C_{6} H_{6}

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