Answer:A force can be described as a push or a pull. Pushes and pulls can be seen to act on objects when they begin to move, speed up, slow down or change direction.
The image gallery on this page shows children at play using push and pull actions to move objects. Children use push and pull all the time while at play. While playing, students learn to manipulate objects and materials and make observations about their actions.
Teachers may use this teaching resource over a number of lessons to explore and develop their students' understanding that a push or a pull affects how an object moves or changes shape.
Explanation:
If the net force on an object is zero, then ...
a). The object's acceleration is zero.
b). The object's velocity is a constant speed in a straight line.
Note: (a) and (b) both say the same thing.
You're average speed would be 6km/hour or 100m per minute.
Under the assumption that the three rocks are dropped from the same height, they will hit the ground at the same speed. The gravity of Earth is virtually the same for any object that is small compared to the size of the Earth. The acceleration will change with the distance from the Earth, but this change is so small for the range of heights we work with (consider the range of heights from sea level to the tip of Mount Everest) that we can take the average value and assume it to be constant. This constant value of acceleration due to Earth's gravity is 9.80665m/s²
Because the objects fall under the same constant acceleration, they will hit the ground at the same speed.
Answer:
The magnitude of the current is 5.45 mA.
Explanation:
Given that,
Resistance = 10.0 ohm
Radius = 0.10 m
Magnetic field = 1.0 T
Angle = 30°
Increase magnetic field = 7.0 T
Time t = 3.0 s
Number of turns = 1
We need to calculate the initial flux
Using formula of flux
Put the value into the formula
We need to calculate the final flux
We need to calculate the induced emf
Using formula of emf
Put the value into the formula
We need to calculate the current
Using formula of current
Put the value into the formula
Hence, The magnitude of the current is 5.45 mA.
