Which process forms sedimentary rock in the rock cycle after sediments accumulate and combine?

Guys I'm in kind of a PICKLE!!!!!! I know people say it a lot but I will give Brainiest to the best explained answer. Determine

Flauer [41]

Answer:

E≅1.2×10^7 N/C

Explanation:

First off I'd like to say that I'm taking "net electric field" to mean that they don't want this answer to be put into vector component form and instead want magnitudes. Sometimes the wording of these questions throws me off, so sorry ahead of time if that's what they want from you!

Edit: I ended up adding it anyways ;P

Since we are observing the net electric field acting at q1, we need to use the formula: $E=k\frac{q}{r^{2} }$

And since we are observing the effects of multiple charges at once...

E=ΣE, which just means wee need to add all the observed electric fields together:

ΣE= $k\frac{q2}{r^{2} } +k\frac{q3}{r^{2} }$

Since we are observing [static] electric fields here, we don't actually need q1's charge. (Though if you wanted to find the net force you would.) Now, before we start plugging values in, let's acknowledge what we know. We know that:

q2=q3
they are the same distance from q1

These are actually really nice to have, because now we can simplify our expression to:

$E=k\frac{2q}{r^{2} }$

Now let's plug in our values and get an answer out.

E= 2(8.99×10^9)(4×10^-5)/(0.24)

Plugging all that in, I get:

E≅1.2×10^7 N/C

If you end up needing the net force, F=(q1)(E). That is, you just multiply the electric field by the value of q1. And again, if your teacher wants the answer in vector component form, then the answer will look different.

Let me know what doesn't make sense, or if I got something wrong. Good luck with AP Phy.!

Edit: I put the component form for my answer in the attachment. I also noticed a small calculator related error in my original answer. I updated that to match the new one.

6 0

3 years ago

Discuss the path that light takes through the human eye

amm1812

The cornea is shaped like a dome and bends light to help the eye focus. Some of this light enters the eye through an opening called the pupil (PYOO-pul). The iris (the colored part of the eye) controls how much light the pupil lets in. Next, light passes through the lens (a clear inner part of the eye).

8 0

2 years ago

Read 2 more answers

Physical therapists know as you soak tired muscles in a hot tub, the water will cool down as you heat up. If a 67.9 person at 37

olga55 [171]

Q1=Q2
m1c1(t-t1)=m2c2(t2-t)
67.9kg * c1* (38.7°C-37.1°C)=50.2kg * 4186 J/kg°C * (40.5°C-38.7°C)
67.9kg* c1 * 1.6°C = 50.2kg * 4186 J/kg°C * 1.8°C
108.64 kg°C * c1 = 378246.96 J
c1 = 378246.96J /108.64kg°C
c1=3481.65 J/kg°C

4 0

3 years ago

Does the magnetic force on the longer sides of the generator loop help or hinder the rotation of the generator loop?

Ilia_Sergeevich [38]

Answer:

Help

Explanation:

We can observe using Fleming's right hand rule that magnetic field line are perpendicular to longer arms and parallel to the shorter arms. Therefore, magnetic force on the long arm will help the rotation of the generator rather than hindering it. No force on the shorter arm as they are parallel to the field lines.

8 0

3 years ago

A ball moves along a table at a constant velocity and then rolls off the edge of the table. The forces that should be included i

Len [333]

Answer:

Gravity

Explanation:

When the ball is falling to the ground, it is already detached from the table, so the table does not exert any force on it.

Gravity is always present, therefore it is acting on the ball (acting downward), so it must be included into the free-body diagram. Apart from that, there are no other forces acting on the ball (if we neglect air resistance, which is negligible, and it is not mentioned in the options given), therefore the only force which has to be included in the diagram is gravity.

3 0

3 years ago