Answer:
In 2.748 sec the mailbag reached the ground
Explanation:
We have given height from the ground
At t =2.25 sec helicopter releases a small mailbag so at t = 2.25 sec height from the ground
When the mail box is drooped its initial velocity would zero so u = 0 m/sec
Acceleration due to gravity
According to third law of motion
t = 2.748 sec
Answer:
Their change in momentum is the same in magnitude and opposite in direction
Explanation:
The momentum of an object is defined as:
where
m is the mass of the object
v is the velocity of the object
Therefore, the change in momentum of an object is
where is the change in velocity.
During a collision, the force experienced by an object is equal to the rate of change of momentum:
where is the duration of the collision.
According to Newton's third law of motion, the force exerted by vehicle 1 on vehicle 2 during the collision is equal (and opposite) to the force exerted by vehicle 2 on vehicle 1, so
Which means
And since the duration of the collision is the same for the two vehicles, this becomes
Answer:
ΔV = 20.1 V
Explanation:
As the positive plates are connected to each other, the capacitors are connected in parallel, so the total system load is the sum of the charges on each capacitor.
Q = Q₁ + Q₂
The charge on each capacitor is
Q₁ = C₁ ΔV₁
Q₁ = 24 10⁻⁶ 25
Q₁ = 6.00 10⁻⁴ C
Q₂ = C₂ ΔV₂
Q₂ = 13 10⁻⁶ 11
Q₂ = 1.43 10⁻⁴ C
The total set charge is
Q = (6 + 1.43) 10⁻⁴
Q = 7.43 10⁻⁴ C
The equivalent capacitance is
C_eq = C₁ + C₂
C_eq = (24 + 13) 10⁻⁶
C_eq = 37 10⁻⁶ F
Let's use the relationship to find the voltage
Q = C_eq ΔV
ΔV = Q / C_eq
ΔV = 7.43 10⁻⁴ / 37 10⁻⁶
ΔV = 2.008 10¹
ΔV = 20.1 V
This voltage is constant in the combination so it is also the voltage in capacitor C1
Answer:
A variable (often denoted by x ) whose variation does not depend on that of another.
Explanation: