All categories

3 years ago

Which is an example of observational learning?

Physics

2 answers:

vekshin13 years ago

8 0

Janice is the one who learned something by watching what was going on in the world around her.

Citrus2011 [14]3 years ago

4 0

<span>Janice saw her older sister get into trouble for breaking curfew and decided she'll never do the same. Because she is learning from her older sisters mistakes!
Hope this helps!!</span>

You might be interested in

3. What distance will a car, traveling 65 km/hr, cover in 3.0 hrs? (195 km)

qwelly [4]

Answer:

$\boxed{\sf Distance \ travelled \ by \ car = 195 \ km}$

Given:

Speed = 65 km/hr

Time = 3.0 hrs

To Find:

Distance

Explanation:

Distance = Speed × Time

= 65 × 3

= 195 km

7 0

4 years ago

Who has the primary responsibility to prepare for emergencies?

Zolol [24]

Answer:

local government agencies

5 0

3 years ago

Help fast plsss ! which statement is true for nuclear reactions but not for chemical reactions?

padilas [110]

Answer:

Explanation: a chemical reaction is only the rearrangement of electrons where a nuclear reaction actually changes the elements and thus the nuclei

5 0

3 years ago

Steam enters an adiabatic turbine steadily at 7 MPa, 5008C, and 45 m/s, and leaves at 100 kPa and 75 m/s. If the power output of

marusya05 [52]

Answer:

a) $\dot m = 6.878\,\frac{kg}{s}$ , b) $T = 104.3^{\textdegree}C$ , c) $\dot S_{gen} = 11.8\,\frac{kW}{K}$

Explanation:

a) The turbine is modelled by means of the First Principle of Thermodynamics. Changes in kinetic and potential energy are negligible.

$-\dot W_{out} + \dot m \cdot (h_{in}-h_{out}) = 0$

The mass flow rate is:

$\dot m = \frac{\dot W_{out}}{h_{in}-h_{out}}$

According to property water tables, specific enthalpies and entropies are:

State 1 - Superheated steam

$P = 7000\,kPa$

$T = 500^{\textdegree}C$

$h = 3411.4\,\frac{kJ}{kg}$

$s = 6.8000\,\frac{kJ}{kg\cdot K}$

State 2s - Liquid-Vapor Mixture

$P = 100\,kPa$

$h = 2467.32\,\frac{kJ}{kg}$

$s = 6.8000\,\frac{kJ}{kg\cdot K}$

$x = 0.908$

The isentropic efficiency is given by the following expression:

$\eta_{s} = \frac{h_{1}-h_{2}}{h_{1}-h_{2s}}$

The real specific enthalpy at outlet is:

$h_{2} = h_{1} - \eta_{s}\cdot (h_{1}-h_{2s})$

$h_{2} = 3411.4\,\frac{kJ}{kg} - 0.77\cdot (3411.4\,\frac{kJ}{kg} - 2467.32\,\frac{kJ}{kg} )$

$h_{2} = 2684.46\,\frac{kJ}{kg}$

State 2 - Superheated Vapor

$P = 100\,kPa$

$T = 104.3^{\textdegree}C$

$h = 2684.46\,\frac{kJ}{kg}$

$s = 7.3829\,\frac{kJ}{kg\cdot K}$

The mass flow rate is:

$\dot m = \frac{5000\,kW}{3411.4\,\frac{kJ}{kg} -2684.46\,\frac{kJ}{kg}}$

$\dot m = 6.878\,\frac{kg}{s}$

b) The temperature at the turbine exit is:

$T = 104.3^{\textdegree}C$

c) The rate of entropy generation is determined by means of the Second Law of Thermodynamics:

$\dot m \cdot (s_{in}-s_{out}) + \dot S_{gen} = 0$

$\dot S_{gen}=\dot m \cdot (s_{out}-s_{in})$

$\dot S_{gen} = (6.878\,\frac{kg}{s})\cdot (7.3829\,\frac{kJ}{kg\cdot K} - 6.8000\,\frac{kJ}{kg\cdot K} )$

$\dot S_{gen} = 11.8\,\frac{kW}{K}$

4 0

3 years ago

Prove that the unit of area derived quantities are derived units

frozen [14]

answer: derived physical quantities are those quantities that are obtained from the basic physical quantities by multiplication or division and area is one of them

8 0

3 years ago