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slava [35]
3 years ago
9

What pressure is required to achieve a co2 concentration of 7.90×10−2 m at 20∘c?

Chemistry
1 answer:
Savatey [412]3 years ago
7 0

Answer:-  1.90 atm

Solution:- It is based on combined gas law equation, PV = nRT

In this equation, P is pressure, V is volume, n is moles of gas, R is universal gas constant and T is kelvin temperature.

If we divide both sides by V then:

P=\frac{nRT}{V}

We know that, molarity is moles per liter. So, in the above equation we could replace \frac{n}{V} by molarity, M of the gas. The equation becomes:

P = MRT

T = 20 + 273 = 293 K

M = 7.9*10^-^2

Let's plug in the values in the equation:

P = (7.9*10^-^2)(0.0821)(293)

P = 1.90 atm

So, the pressure of the gas is 1.90 atm.

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Q is 0.5 and K is 0.01, therefore K is less than Q.

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for O₂ : 0.1 mole per 1L container = 0.1 mol/L = 0.1M

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finally, we are going to compare the value of Q with K

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if K<Q , the reaction will proceed backward, converting products into reactants.

if K=Q , the system of reaction is already in equilibrium.

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the system will proceed in the reverse direction, thereby converting products into reactants. converting Nitric oxide to form oxygen and nitrogen.

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but hope this helps

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