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slava [35]
3 years ago
9

What pressure is required to achieve a co2 concentration of 7.90×10−2 m at 20∘c?

Chemistry
1 answer:
Savatey [412]3 years ago
7 0

Answer:-  1.90 atm

Solution:- It is based on combined gas law equation, PV = nRT

In this equation, P is pressure, V is volume, n is moles of gas, R is universal gas constant and T is kelvin temperature.

If we divide both sides by V then:

P=\frac{nRT}{V}

We know that, molarity is moles per liter. So, in the above equation we could replace \frac{n}{V} by molarity, M of the gas. The equation becomes:

P = MRT

T = 20 + 273 = 293 K

M = 7.9*10^-^2

Let's plug in the values in the equation:

P = (7.9*10^-^2)(0.0821)(293)

P = 1.90 atm

So, the pressure of the gas is 1.90 atm.

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Without consulting Appendix B, arrange each group in order of increasing standard molar entropy (S°). Explain.(c) SF₆(g), SF₄(g)
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The increasing order of standard molar entropy (S°) is as follow:

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<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

The standard molar entropy depends on the molas mass of atom, molecules or compound.

SF₄(g) has lower standard molar entropy. Due to less complexity of this molecules.

While, complexity increases from SF₆(g) to S₂F₁₀(g). Therefore, the standard molar entropy of S₂F₁₀(g) is greater than SF₆(g).

Thus, we concluded that the increasing order of standard molar entropy (S°) is as follow:

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learn more about standard molar entropy:

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