Answer:

Explanation:
A pressure of 1 atm and a temperature of 0 °C is the old definition of STP. Under these conditions, 1 mol of a gas occupies 22.4 L.
1. Calculate the moles of hydrogen.

2. Calculate the number of molecules

Answer:
0.19 g
Explanation:
Step 1: Given data
Volume of hydrogen at standard temperature and pressure (STP): 2.1 L
Step 2: Calculate the moles corresponding to 2.1 L of hydrogen at STP
At STP (273.15 K and 1 atm), 1 mole of hydrogen has a volume of 22.4 L if we treat it as an ideal gas.
2.1 L × 1 mol/22.4 L = 0.094 mol
Step 3: Calculate the mass corresponding to 0.094 moles of hydrogen
The molar mass of hydrogen is 2.02 g/mol.
0.094 mol × 2.02 g/mol = 0.19 g
Answer:
Condensation
Explanation:
During condensation the water vapor in the air converts to liquid, this forms clouds.
You can also refer to the attached image for more validation.
Answer:
The volume will be 568.89 mL.
Explanation:
Boyle's law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
or P * V = k
Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. That is, the pressure of the gas is directly proportional to its temperature. Gay-Lussac's law can be expressed mathematically as follows:
Where P = pressure, T = temperature, K = Constant
Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

Studying an initial state 1 and a final state 2, it is fulfilled:

In this case:
- P1= 960 mmHg
- V1= 550 mL
- T1= 200 C= 473 K (being 0 C=273 K)
- P2= 830 mmHg
- V2= ?
- T2= 150 C= 423 K
Replacing:

Solving:

V2= 568.9 mL
<u><em>The volume will be 568.89 mL.</em></u>