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Brums [2.3K]
2 years ago
11

If 10.7 grams of NH4Cl is dissolved in enough water to make 800 mL of solution,what will be it's molarity

Chemistry
1 answer:
olga nikolaevna [1]2 years ago
6 0
<h3><u>Answer;</u></h3>

Molarity = 0.25 M

<h3><u>Explanation;</u></h3>

Molarity is given by moles/Liter.

First we find moles:

Number of moles = Mass /molar mass

= (10.7g NH4Cl)/(53.5g/mol NH4Cl)

= 0.200 moles NH4Cl  

Then  we convert to liters:

= (800mL)*(1L/1000mL) = 0.800L  

Therefore; molarity = 0.2moles/0.8L

                                = 0.25M

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hat is the pressure of CO(g) in equilibrium with the CO2(g) and O2(g) in the atmosphere at 25 ????C? The partial pressure of O2(
Lubov Fominskaja [6]

Answer:

The partial pressure of CO is 5.54x10⁻⁴⁹atm. You shouldn't worry because it is very low pressure

Explanation:

First, the balanced reaction is:

CO + 1/2O₂ → CO₂

The energies of formation are:

ΔG(CO)=-137.168kJ/mol

ΔG(O₂)=0

ΔG(CO₂)=-394.359kJ/mol

The energy of the reaction is:

delta-G_{reaction} =delta-G_{CO_{2} } -(delta-G_{CO} +1/2delta-G_{O_{2} } )\\delta-G_{reaction}=-394.359-(-137.168+0)=-257.191kJ/mol

The expression for calculate the partial pressure of CO is:

p_{CO} =\frac{p_{CO2} }{p_{O_{2} }^{1/2}*exp^{-\frac{delta-G}{RT} }   } \\p_{CO}=\frac{3x10^{-4} }{0.2^{1/2}*exp(-\frac{-257.191*1000}{8.314*298} ) } \\p_{CO}=5.54x10^{-49} atm

5 0
2 years ago
Question 12 of 25
Tomtit [17]

Answer:

B

Explanation:

All atoms are divisible

6 0
2 years ago
A compound is found to contain 38.65 % carbon, 16.25 % hydrogen, and 45.09 % nitrogen by mass. what is the empirical formula for
iren [92.7K]

The molar mass of carbon is 12, hydrogen is 1, and nitrogen is 14, hence the ratio are:

 

C = 38.65 / 12 = 3.22

H = 16.25 / 1 = 16.25

N = 45.09 / 14 = 3.22

 

Divide the three by the lowest ratio which is 3.22:

 

C = 3.22 / 3.22 = 1

H = 16.25 / 3.22 = 5

N = 3.22 / 3.22 = 1

 

So the empirical formula is:

CHN

5 0
3 years ago
Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH
Doss [256]

Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

    No. of moles = \frac{mass}{\text{molar mass}}

                           = \frac{12 g}{60 g/mol}

                           = 0.2 mol

Molarity of acetic acid is calculated as follows.

              Density = \frac{mass}{volume}

                 1 g/ml = \frac{100 g}{volume}

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As reaction equation for the given reaction is as follows.

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So,          moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

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                        x = 20 L

Thus, we can conclude that volume of NaOH required is 20 ml.                    

6 0
3 years ago
An alloy is a mixture that has
defon

Answer:

an alloy is a mixture of elements that has metallic properties

Explanation:

8 0
2 years ago
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