Can y’all help me with this last bit of my hw? I don’t really understand it and I would really appreciate it if you could help m
e.
The questions to the picture is below:
A chemist mixer two substances together: a colorless liquid with a strong strong smell and a white solid with no smell. The substances’ repeating groups of atoms are shown on the left. After they were mixed, the chemist analyzed the results and found two substances, One ending substance had the resorting group of atoms shown above on the right.
Is the ending substance the same as the colorless liquid? What happened to the atoms of the starting substances when the ending substances formed? Be sure to explain your answers to both of these questions.
The questions to the picture is below:
A chemist mixer two substances together: a colorless liquid with a strong strong smell and a white solid with no smell. The substances’ repeating groups of atoms are shown on the left. After they were mixed, the chemist analyzed the results and found two substances, One ending substance had the resorting group of atoms shown above on the right.
Is the ending substance the same as the colorless liquid? What happened to the atoms of the starting substances when the ending substances formed? Be sure to explain your answers to both of these questions.
1 answer:
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Answer: The empirical formula for the given compound is
Explanation:
The chemical equation for the combustion of compound having carbon and hydrogen follows:
where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.
We are given:
Mass of
We know that:
Molar mass of carbon dioxide = 44 g/mol
For calculating the mass of carbon:
In 44 g of carbon dioxide, 12 g of carbon is contained.
So, in 22.0 g of carbon dioxide, of carbon will be contained.
For calculating the mass of hydrogen:
Mass of hydrogen = Mass of sample - Mass of carbon
Mass of hydrogen = 7.0 g - 6 g
Mass of hydrogen = 1.0 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.
For Carbon =
For Hydrogen =
Step 3: Taking the mole ratio as their subscripts.
The ratio of Fe : C : H = 1 : 2
Hence, the empirical formula for the given compound is