Answer:
The volume of NaOH required is - 0.01 L
Explanation:
At equivalence point
,
Moles of
= Moles of NaOH
Considering
:-
Given that:
So,
<u>The volume of NaOH required is - 0.01 L</u>
30.07 g/mol (that’s grams per mole)
ANS: density = 13.41 g/ml
Density (d) of a substance is the mass (m) occupied by it in a given volume (v).
Density = mass/volume
i.e. d = m/v
m = (d) v -----(1)
The given equation from the plot of weight vs volume is :
y = 13.41 x ----(2)
Based on equations (1) and (2) we can deduce that the density of the metal is 13.41 g/ml
The correct answer is d) chrima