In a group 1 analysis, a student obtained a precipitate containing both AgCl and PbCh. Which of the following reagents would ena
1 answer:
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<u>Answer:</u> The amount of water required to prepare given amount of salt is 398.4 mL
<u>Explanation:</u>
To calculate the volume of solution, we use the equation used to calculate the molarity of solution:
We are given:
Molarity of solution = 0.16 M
Given mass of manganese (II) nitrate tetrahydrate = 16 g
Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol
Putting values in above equation, we get:
Volume of water = Volume of solution = 398.4 mL
Hence, the amount of water required to prepare given amount of salt is 398.4 mL
<u>Answer:</u> The correct answer is Option D.
<u>Explanation:</u>
We are given that car travels with a speed of 80 km/hr and we need to convert it into hm/s.
For that we use the conversions:
1 kilometer = 10 hectometer
And, 1 hour = 3600 seconds
To convert the quantity into hm/s, we multiply the numerator which is 80 by 10 to convert the whole quantity into hm/hr and now, to convert the result into hm/s finally, we divide the result by 3600.
Hence, the correct answer is option D.