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gayaneshka [121]
3 years ago
12

In a group 1 analysis, a student obtained a precipitate containing both AgCl and PbCh. Which of the following reagents would ena

ble separation of AgCl(s) from PbCl(s)? O Hys 0 Na2CO3 o KOH O NH3 O
Chemistry
1 answer:
kakasveta [241]3 years ago
6 0

Answer:

We can separate AgCl and PbCl₂ by adding hot water.

Explanation:

In order to separate group one salts/ions is important to consider their solubility.

PbCl₂ is more soluble in water then AgCl and, when we increase water's temperature, PbCl₂ solubility icireases significantly. However, AgCl solubility does not change considerably.

Therefore, when we add hot water to the solution, the PbCl₂ will be dissolved and AgCl will remain as a precipitate.

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The molarity of the solution will be 0.72 m.

The majority of reactions take place in solutions, making it crucial to comprehend how the substance's concentration is expressed in a solution when it is present. The number of chemicals in a solution can be stated in a variety of ways, including.

The symbol for it is M, and it serves as one of the most often used concentration units. Its definition states how many moles of solute there are in a liter of solution.

Given data:

V_{1} =57.3 L\\V_{2} = 39.5 L\\M_{1} = 0.497 m\\\\M_{2} = ?

Molarity can be determined by the formula:

M_{1} V_{1} = M_{2} V_{2}

where, M is molarity and V is volume.

Put the value of given data in above equation.

57.3 × 0.497 m = M × 39.5 L

M = 0.72 m

Therefore, the molarity of the solution will be 0.72 m

To know more about molarity

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