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3 years ago

6

Why does the sun seem to change position in the sky?

2 answers:

Blababa [14]3 years ago

7 0

The first major contributor to the Sun's apparent motion is the fact that Earth orbits the Sun while tilted on its axis. The Earth's axial tilt of approximately 23.5° ensures that observers at different locations will see the Sun reach higher-or-lower positions above the horizon throughout the year.

hope this helps ^^

Bezzdna [24]3 years ago

6 0

Answer:

Because the earth rotation, when we move around the sun for a whole 365 times then we will have passed 1 year.

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An airplane travels with a constant velocity of 210 m/s and in the upper atmosphere where the plane is traveling there is a wind

kolezko [41]

Answer:

hello your question is incomplete the options are missing

Determine the resultant velocity for the plane when it is travelling

i) To the east

ii) To the west

answer :i) 270 i

ii) -150 i

Explanation:

velocity of Airplane = 210 m/s

wind velocity = 60 m/s to the east

The resultant velocity for the plane when it is travelling

let the velocity of the wind = V2

velocity of the plane = v1

i) The resultant velocity for the plane when travelling to the east

Vr = V2 i + V1 i

Vr= 60i + 210i = 270i

ii) resultant velocity when the plane is travelling to the west

Vr = - V1 i + V2i

= -210i + 60 i = -150 i

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3 years ago

What isapplied in case where the base is not a OH donator

blagie [28]

It will received an H+. I’m not sure if that answers your question correctly

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3 years ago

Calculate the standard free-energy change at 25 ∘C for the following reaction:

lianna [129]

Answer:

Standard free-energy change at $25^{0}\textrm{C}$ is $-3.80\times 10^{2}kJ/mol$

Explanation:

Oxidation: $Mg(s)-2e^{-}\rightarrow Mg^{2+}(aq.)$

Reduction: $Fe^{2+}(aq.)+2e^{-}\rightarrow Fe(s)$

--------------------------------------------------------------------------------------

Overall: $Mg(s)+Fe^{2+}(aq.)\rightarrow Mg^{2+}(aq.)+Fe(s)$

Standard cell potential, $E_{cell}^{0}=E_{Fe^{2+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}$

So, $E_{cell}^{0}=(-0.41V)-(-2.38V)=1.97V$

We know, standard free energy change at $25^{0}\textrm{C}$ ( $\Delta G^{0}$ ): $\Delta G^{0}=-nFE_{cell}^{0}$

where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol

Here n = 2

So, $\Delta G^{0}=-(2)\times (96500C/mol)\times (1.97V)=-380210J/mol=-380.21kJ/mol=-3.80\times 10^{2}kJ/mol$

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3 years ago

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o-na [289]

Answer:

A

Explanation:

increase in energy - hotter and/or more reactive

decrease in energy - colder and/or less reactive

Since it is going from a liquid to solid it will have a tighter arrangement of particles.

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2 years ago

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GarryVolchara [31]

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2 years ago

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