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Andrej [43]
3 years ago
13

Which of these can be classified as a pure substance? Help please

Chemistry
2 answers:
saw5 [17]3 years ago
4 0

Answer: The answer is salt

nikdorinn [45]3 years ago
4 0
The pure substance is salt.
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The properties of two elements are listed below. Element Atomic radius (pm) Ionic radius (pm) First ionization energy (kJ/mol) E
Sedbober [7]

Answer:

K will give up an electron more easily than Br.

Explanation:

Electronegativity of an element is a property that combines the ability of its atom to lose and gain electrons.

The lower the electronegativity value, the more electropositive an element is and the more readily it loses electrons.

From the data given, we see that Br has an E.N value of 3.0 and K has an E.N value of 0.82.

Therefore, Br is highly electronegative and it is able to attract electrons to itself whereas K has a low E.N value. K will give up electrons more readily.

Lookinf at other information in the table, the larger atomic radius and lower ionizaton energy of K are all pointers to how readily it would be able to lose electrons.

We can conclude that K is even a metal.

5 0
3 years ago
A(n)
Sonja [21]
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8 0
3 years ago
When the weather change and temperatures get hot what do wolves use to cool down
shusha [124]
When the seasons change from winter to spring, the wolves inner layer of fur, which traps air and insulates the wolf from harsh cold temperatures, is shed to keep the wolf cool when the heat starts to come back. 
7 0
3 years ago
Read 2 more answers
A waste treatment pond is 50 m long and 25 m wide, and has an average depth of 2 m. The density of the waste is 75.3lbm/ft^3 .Ca
umka21 [38]

Answer:

W = 6.65 \cdot 10^{6} lbf

Explanation:

To find the weight (W) of the pond contents first we need to use the following equation:

W = m\cdot g   (1)

Where m the mass and g is the gravity  

Also, we have that the mass is:

m = \rho*V  (2)    

Where ρ is the density and V the volume

We cand calculate the volume as follows:

V = L*w*d   (3)

Where L is the length, w is the wide and d is the depth  

By entering equation (2) and (3) into (1) we have:

W = \rho*L*w*d*g

W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2}  

W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf              

Therefore, the weight of the pond is 6.65x10⁶ lbf.

I hope it helps you!

6 0
4 years ago
Study the solutions in the glasses. Put the solutions in order from concentrated to dilute.
Svetach [21]
A. 1,2,3. The solutions are getting lighter meaning the concentration is decreasing. Its most likely that water was added to dilute the solutions.
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3 years ago
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