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igomit [66]
2 years ago
12

Newton's Third Law of Motion relates to action and reaction. Which of the following scenarios accurately names the correct actio

n and reaction pair to apply to Newton's Third Law?
Physics
1 answer:
Tomtit [17]2 years ago
5 0
Newton’s Third Law of Motion states that for every action there is an equal and opposite reaction. So look for a scenario in which something had force applied upon it and the reaction is a force in the opposite direction of the same size.
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A satellite is acted upon by a 10n force upwards and 20n force downwards. What is the net force acting on the satellite and what
Lina20 [59]

Answer:

Net force = 10 N in downward direction

Explanation:

Given that,

Upward force = 10 N

Downward force = 20 N

Let downward is negative and upward is positive.

Net force = 10+(-20)

= -10 N

So, the net force is 20 N and it is acting in downward direction.

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3 years ago
Heat will flow from a hot object to a cold object until the objects reach
leonid [27]

Answer:

(The first law of thermodynamics) When you put a hot object in contact with a cold one, heat will flow from the warmer to the cooler. As a result, the warmer one will usually cool down and the cooler one will usually warm up. Eventually, they will reach the same temperature and heat flow will stop.

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andrezito [222]

Answer:

20 n

Explanation:

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2 years ago
Prepare a summary to explain how much the final birds varied from the original birds after 1 million years of natural selection.
mezya [45]

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your father️️️ just 5 points

5 0
3 years ago
Help with these three
Elenna [48]
The first: alright, first: you draw the person in the elevator, then draw a red arrow, pointing downwards, beginning from his center of mass. This arrow is representing the gravitational force, Fg.
You can always calculate this right away, if you know his mass, by multiplying his weight in kg by the gravitational constant
g = 9.81 \frac{m}{s {}^{2} }
let's do it for this case:
f_{g}  = m \times g \\ f _{g}  = 65kg \times 9.81 \frac{m}{s {}^{2} }  = 637.65
the unit of your fg will be in Newton [N]
so, first step solved, Fg is 637.65N
Fg is a field force by the way, and at the same time, the elevator is pushing up on him with 637.65N, so you draw another arrow pointing upwards, ending at the tip of the downwards arrow.
now let's calculate the force of the elevator
f = m \times a \\ f = 65 \times 5 \frac{m}{s {}^{2} }  \\ f = 325n
so you draw another arrow which is pointing downwards on him, because the elevator is accelating him upwards, making him heavier
the elevator force in this case is a contact force, because it only comes to existence while the two are touching, while Fg is the same everywhere
8 0
3 years ago
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