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musickatia [10]
3 years ago
9

What force accelerates a 500 kg object at 5 m/s2?

Physics
2 answers:
Alexxx [7]3 years ago
7 0

Answer:

2500N

Explanation:

f = m.a

m=500 kg

a=5 m/s²

f = 5*500 kgm/s² = 2500 N

Llana [10]3 years ago
4 0

For this case we have that by definition, Newton's second law states that:

F = m * a

Where:

F: Force

m: Mass

a: Acceleration

According to the data we have to:

m = 500 \ kg\\a = 5 \frac {m} {s ^ 2}

Substituting we have:

F = 500kg * 5 \frac {m} {s ^ 2}\\F = 2,500N

ANswer:

The necessary force is 2,500N

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With the switch open, there's no current in the circuit, and therefore
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3 years ago
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3. A 900N mountain climber scales a
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Answer:

<h2>135,000 J</h2>

Explanation:

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workdone = force × distance

From the question we have

workdone = 900 × 150

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<h3>135,000 J</h3>

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2 years ago
How do you determine true displacement value of an object that has moved?
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3 years ago
For work to be accomplished we must have
Nat2105 [25]
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A 300 g glass thermometer initially at 23 ◦C is put into 236 cm3 of hot water at 87 ◦C. Find the final temperature of the thermo
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Answer:

74^{\circ} C

Explanation:

We are given that

Mass of glass,m=300 g

T_1=23^{\circ}

Volume,V=236cm^3

Mass of water=density\times volume=1\times 236=236 g

Density of water=1g/cm^3

Temperature of hot water,T=87^{\circ}

Specific heat of glass,C_g=0.2cal/g^{\circ}C

Specific heat of water,C_w=1 cal/g^{\circ}C

Q_{glass}=m_gC_g(T_f-T_1)=300\times 0.2(T_f-23)

Q_{water}=m_wC_w(T_f-T)=236\times 1(T_f-87)

Q_{glass}+Q_{water}=0

300\times 0.2(T_f-23)+236\times 1(T_f-87)

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