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musickatia [10]
3 years ago
9

What force accelerates a 500 kg object at 5 m/s2?

Physics
2 answers:
Alexxx [7]3 years ago
7 0

Answer:

2500N

Explanation:

f = m.a

m=500 kg

a=5 m/s²

f = 5*500 kgm/s² = 2500 N

Llana [10]3 years ago
4 0

For this case we have that by definition, Newton's second law states that:

F = m * a

Where:

F: Force

m: Mass

a: Acceleration

According to the data we have to:

m = 500 \ kg\\a = 5 \frac {m} {s ^ 2}

Substituting we have:

F = 500kg * 5 \frac {m} {s ^ 2}\\F = 2,500N

ANswer:

The necessary force is 2,500N

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7 0
3 years ago
Read 2 more answers
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3 years ago
A 740-kg boulder is raised from a quarry 119 m deep by a long uniform chain having a mass of 550 kg . This chain is of uniform s
Naddika [18.5K]

Answer:

A) the maximum acceleration the boulder can have and still get out of the quarry

B) how long does it take to be lifted out at maximum acceleration if it started from rest

Explanation:

A)

let +y is upward. look below at the free body diagram. the mass M refers to the combined mass of the boulder and chain.

the weight of the chain is:   w_{c} =m_{c} g   and maximum tension is T=2.50 m_{c} g=1.41*10^4N

total mass and weight is :

M =m_{c}+ m_{b} =740kg+550kg=1290 kg

w_{M} =1.2650*10^4N

∑F_{y} =ma_{y}

T-M_{g} =Ma_{y}

a_{y} =(t-M_{g} )/M=(2.50m_{c} -M_{g} )/M=(2.50.550kg-1290kg)(9.8m/s^2)/1290kg

=0.645m/s^2

B)

maximum acceleration

a_{y} =0.645m/s^2\\\\y-y_{0} =119m\\v_{0y} =0

using y-y_{0} =v_{oy} t+1/2(a_{y} )t^2

to solve for t

t=\sqrt{2(y-y_{0} )/a_{y} }

t=\sqrt{2(119m)/0.645m/s^2} =19.20s

6 0
3 years ago
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alukav5142 [94]

Answer:

A new substance was formed

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According to this question, a shiny and flexible metal called Magnesium (Mg) is burnt in air to produce a white powder that has no shiny or flexible properties, however, has more weight than the magnesium metal itself.

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