Velocity is the rate of change in distance over change in
time, this can be written as:
v = Δd / Δt
While acceleration is the rate of change in velocity over
change in time, this is written as:
a = Δv / Δt
<span>Both quantities are vector quantities because negative
values means that the acceleration or velocity is acting on the opposite
direction.</span>
Answer:
The time of the second observer at the end of the car motion is 27 s
Explanation:
Initial time of the first observer, t₁ = 262 s
final time of the first observer, t₂ = 375 s
The time of the car motion, t = t₂ - t₁
t = 375 s - 262 s
t = 113 s
Initial time of the second observer, t₁ = -86 s
final time of the second observer, t₂ = ?
The time of the car motion, t = t₂ - t₁
113 = t₂ - t₁
113 = t₂ - (-86)
113 = t₂ + 86
t₂ = 113 - 86
t₂ = 27 s
Therefore, the time of the second observer at the end of the car motion is 27 s
Answer:
Explanation:
Given that,
Force, F = 52 N
Mass of the block, m = 4 kg
We need to find the acceleration of the object. We know that,
F = ma
Put the values,
So, the acceleration of the object is equal to 
.
What are you asking here?
Answer:
k=320N/m
Explanation:
Step one:
given data
Let the initial/equilibrum position be x
mass m1= 0.2kg
F1= 0.2*10= 2N
elongation e= 9.5cm= 0.095m
mass m2=1kg
F2=1*10= 10N
elongation e= 12cm= 0.12m
Step two:
From Hooke's law, which states that provided the elastic limits of a material is not exceeded the extention e is proportional to applied Force F
F=ke
2=k(0.095-a)
2=0.095k-ka----------1
10=k(0.12-a)
10=0.12k-ka----------2
solving equation 1 and 2 simultaneously
10=0.12k-ka----------2
- 2=0.095k-ka----------1
8=0.025k-0
divide both side by 0.025
k=8/0.025
k=320N/m
