Answer:
1.08
Explanation:
This is the case of interference in thin films in which interference bands are formed due to constructive interference of two reflected light waves , one from upper layer and the other from lower layer . If t be the thickness and μ be the refractive index then
path difference created will be 2μ t.
For light coming from rarer to denser medium , a phase change of π occurs additionally after reflection from denser medium, here, two times, once from upper layer and then from the lower layer , so for constructive interference
path diff = nλ , for minimum t , n =1
path diff = λ
2μ t. = λ
μ = λ / 2t
= 626 / 2 x 290
= 1.08
The formula is:
W = p * ΔV, where W stays for work, p stays for the pressure and ΔV is the change of volume in the piston.
We know that : W = 0.6 J.
The piston has a diameter: 1.8 cm. It means that : r = 0.9 cm.
It travels 2.3 cm, so the height of a cylinder is: h = 2.3 cm.
ΔV = r² · π · h = 0.9² · 3.14 · 2.3 = 5.85 cm³ = 0.00000585 m³
The pressure:
p = W / V = 0.6 J / 0.00000585 m³ = 103,448.27 Pa
p = 103.45 kPa
Answer: The pressure of the steam is 103.45 kPa.
Answer:
The compression of the spring is 24.6 cm
Explanation:
magnitude of the charge on the left, q₁ = 4.6 x 10⁻⁷ C
magnitude of the charge on the right, q₂ = 7.5 x 10⁻⁷ C
distance between the two charges, r = 3 cm = 0.03 m
spring constant, k = 14 N/m
The attractive force between the two charges is calculated using Coulomb's law;
The extension of the spring is calculated as follows;
F = kx
x = F/k
x = 3.45 / 14
x = 0.246 m
x = 24.6 cm
The compression of the spring is 24.6 cm
