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3 years ago

The greater the amplitude of a wave, the greater its

Physics

1 answer:

agasfer [191]3 years ago

7 0

The greater the amplitude of a wave, the greater its D) energy

Explanation:

- The amplitude of a wave is the maximum displacement of the wave with respect to the equilibrium position. It is generally indicated with A.

The energy of a wave is proportional to the square of its amplitude:

$E=\propto A^2$

Therefore, we immediately see that option D) is the correct one: the greater amplitude of the wave, the greater its energy.

The other quantities of a wave are:

- Frequency: it is the number of complete cycles of the wave per second

- Wavelength: it is the distance between two crests of the wave

- Speed: the speed of a wave is calculated using the equation

$v=f \lambda$

where f is the frequency and $\lambda$ is the wavelength.

Learn more about waves:

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umka2103 [35]

Answer:

None.

Explanation:

Gravitational potential energy, depends only of the mass on which the gravity is doing work, and the displacement produced by this force.
As displacement depends only on the final and initial positions (in this case, the height of the hill), if we choose as our zero reference level the bottom of the hill, the change in gravitational potential energy will be as follows:

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As we can see, the only value of distance involved is the height of the hill , so it is independent of the distance travelled.

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3 years ago

A cat runs and jumps from one roof top to another which is 5 m away and 3 m below. Calculate the minimum horizontal speed with w

icang [17]

ThIs is the same type of problem
find out the time value
3 = 1/2*a*T^2
6/10 = t^2
t = 0.77 seconds
and the distance is given 5 m
thus speed ,= distance/time
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3 years ago

A block weighs 15 n and is suspended from a spring that is attached to the ceiling. the spring stretches by 0.075 m from its uns

Illusion [34]

We can salve the problem by using the formula:

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From the first situation we can calculate the spring constant, which is given by the ratio between the force applied and the stretching of the spring:

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By using the value of the spring constant we calculated in the first step, we can calculate the new stretching of the spring when a force of 33 N is applied:

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