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2 years ago

The greater the amplitude of a wave, the greater its

Physics

1 answer:

agasfer [191]2 years ago

7 0

The greater the amplitude of a wave, the greater its D) energy

Explanation:

- The amplitude of a wave is the maximum displacement of the wave with respect to the equilibrium position. It is generally indicated with A.

The energy of a wave is proportional to the square of its amplitude:

$E=\propto A^2$

Therefore, we immediately see that option D) is the correct one: the greater amplitude of the wave, the greater its energy.

The other quantities of a wave are:

- Frequency: it is the number of complete cycles of the wave per second

- Wavelength: it is the distance between two crests of the wave

- Speed: the speed of a wave is calculated using the equation

$v=f \lambda$

where f is the frequency and $\lambda$ is the wavelength.

Learn more about waves:

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An engineer in India (standard household voltage = 220 volts) is designing a transformer for use on her

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2 years ago

Physics. Need help. Brainlieast answer for most/ all of the answers answered

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<u>ALL of the following work assumes NO AIR RESISTANCE:</u>

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2). a parabola

3). Horizontal: velocity is constant, acceleration is zero. . . . Vertical: acceleration is 9.8 m/s² downward, velocity depends on whether it was launched, thrown up, thrown down, dropped, etc.

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2 years ago

A charged particle moves in a circular path in a uniform magnetic field.Which of the following would increase the period of the

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Answer:

Increasing its charge

Increasing the field strength

Explanation:

For a charged particle moving in a circular path in a uniform magnetic field, the centripetal force is provided by the magnetic force, so we can write:

$qvB = m\frac{v^2}{r}$

where

q is the charge

v is the velocity

B is the magnetic field

m is the mass

r is the radius of the orbit

The period of the motion is

$T=\frac{2\pi r}{v}$

Re-arranging for r

$r=\frac{Tv}{2\pi}$

And substituting into the previous equation

$qvB = m \frac{Tv^3}{2\pi}$

Solving for T,

$T=\frac{2\pi q B}{m v^2}$

So we see that the period is:

- proportional to the charge and the magnetic field

- inversely proportional to the mass and the square of the speed

So the following will increase the period of the particle's motion:

Increasing its charge

Increasing the field strength

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2 years ago

Determine the angular velocity ω of the telescope as it orbits around the Sun.

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2 years ago