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Elenna [48]
3 years ago
8

When condensation rates decrease, causing fewer clouds to form, how might humans change their behavior?

Physics
2 answers:
Soloha48 [4]3 years ago
8 0

Explanation:

Humans might hold picnic outside in the bright sunny daylight and enjoy their day with family and friends. People will relax and will spend time with their near and dear ones. Less condensation means no rainfall, so people will also do few works that they have been willing to do but could not do due to rainfall. Thus people will be in a happy mood doing their work and spending their time with close ones. A sense of positiveness and happiness will surround the atmosphere.

Lubov Fominskaja [6]3 years ago
5 0
<span>Humans might hold a picnic outside because of a lack of precipitation.</span>
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Westinghouse and Edison fought what was known as the war of the currents. Eventually, Westinghouse triumped using Alternating Cu
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3 years ago
1) The equilibrium constant Kc for the reaction N 2(g) + O 2(g) 2NO(g) at 1200 C is 1.00x 10^-5. Calculate the molar concentrati
Elina [12.6K]

Explanation:

1) N₂ + O₂ → 2 NO

Kc = [NO]² / ([N₂] [O₂])

Set up an ICE table:

\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\N_{2}&0.114&-x&0.114-x\\O_{2}&0.114&-x&0.114-x\\NO&0&+2x&2x\end{array}\right]

Plug into the equilibrium equation and solve for x.

1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))

1.00×10⁻⁵ = (2x)² / (0.114 − x)²

√(1.00×10⁻⁵) = 2x / (0.114 − x)

0.00316 = 2x / (0.114 − x)

0.00361 − 0.00316x = 2x

0.00361 = 2.00316x

x = 0.00018

The volume is 1.00 L, so the concentrations at equilibrium are:

[N₂] = 0.114 − x = 0.11382

[O₂] = 0.114 − x = 0.11382

[NO] = 2x = 0.00036

2(a) Cl₂ → 2 Cl

Kc = [Cl]² / [Cl₂]

\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\Cl_{2}&2.0&-x&2.0-x\\Cl&0&+2x&2x\end{array}\right]

1.2×10⁻⁷ = (2x)² / (2 − x)

1.2×10⁻⁷ (2 − x) = 4x²

2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²

2.4×10⁻⁷ ≈ 4x²

x² ≈ 6×10⁻⁸

x ≈ 0.000245

2x ≈ 0.00049

2(b) F₂ → 2 F

Kc = [F]² / [F₂]

\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\F_{2}&2.0&-x&2.0-x\\F&0&+2x&2x\end{array}\right]

1.2×10⁻⁴ = (2x)² / (2 − x)

1.2×10⁻⁴ (2 − x) = 4x²

2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²

2.4×10⁻⁴ ≈ 4x²

x² ≈ 6×10⁻⁵

x ≈ 0.00775

2x ≈ 0.0155

F₂ dissociates more, so Cl₂ is more stable at 1000 K.

7 0
3 years ago
A rocket is fired straight upward, starting from rest with an acceleration of 25.0 m/s^2. It runs out of fuel at the end of 4.00
ANTONII [103]

Answer:

a) 200m, 100m/s

b) 710.20m

c) -117.98 m/s

d) 26.24 s

Explanation:

To solve this  we have to use the formulas corresponding to a uniformly accelerated motion problem:

V=Vo+a*t (1)

X=Xo+Vo*t+\frac{1}{2}*a*t^2\\ (2)

V^2=Vo^2+2*a*X (3)

where:

Vo is initial velocity

Xo=intial position

V=final velocity

X=displacement

a)

X=0+0*4+\frac{1}{2}*25*4^2

the intial position is zero because is lauched from the ground and the intial velocitiy is zero because it started from rest.

X=200m

V=0+25*4

V=100m/s

b)

The intial velocity is 100m/s we know that because question (a) the acceleration is -9.8\frac{m}{s^2} because it is going downward.

0=100^2+2*(-9.8)*X\\X=510.20\\totalheight=200+510.20=710.20m

c)

In order to find the velocity when it crashes, we can use the formula (3).

the initial velocity is 0 because in that moment is starting to fall.

V^2=0^2+2*(-9.8)*(710.20)\\V=-117.98 m/s

the minus sign means that the object is going down.

d)

We can find the total amount of time adding the first 4 second and the time it takes to going down.

to calculate the time we can use the formula (2) setting the reference at 200m:

-200=0+100*t+\frac{1}{2}*(-9.8)*t^2

solving this we have: time taken= 22.24 seconds

total time is:

total=22.24+4=26.24 seconds.

3 0
2 years ago
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