How to find the volume of an irregular solid

1 answer:

8 0

Use water displacement.
First, measure the amount of water in a graduated cylinder.
Second, place the object in the water.
Third, measure the amount of water in the graduated cylinder currently.
Fourth, subtract the original amount of water from the risen amount of water.
This will calculate the volume.

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A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being

Igoryamba

Answer:

A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being supersaturaded

Explanation:

This question is about solubility.

Regarding solubility, the solutions may be classified as:

Unsaturated: the concentration is below the maximum concentration permited at the given temperature.

Saturated: the concentration is the maximum permitted at the given temperature, under normal conditions.

Supersaturated: the concentration has overcome the maximum permitted at the given temperature. This is possible only under special conditions and is a very unstable state.

Each substance has its own, unique solubility properties. So, in order to tell the state of the solution you need to compare with either solubility tables, or solubility curves; or run you own experiments.

In internet you can find the solubility curve of NaNO₃ showing the solubility for a wide range of temperatures.

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Hence, do the proportion to determine the amount of solute that can be dissolved in 50 grams of water at 50°CÑ

115 g NaNO₃ / 100 g H₂O = x / 50 g H₂O ⇒ x = 57.5 g NaNO₃

Conclusion: 50 grams of water can contain 57.5 g of NaNO₃ dissolved; so, a solution containing 60 g of NaNO₃ completely dissolved in 50 grams of water is supersaturated.

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