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Alinara [238K]
3 years ago
13

Match reagents as starting materials for the synthesis of ethyl 3-phenyl-3-oxopropanate. You can draw out the structures on your

own to help you answer this question.
Premise Response
1 Methyl benzoate = A Acetophenone
2 Diethyl carbonate = B Ethyl acetate
Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Explanation:

Transcribed image text: H26.25 - Level 2 Homework. Unanswered Match reagents as starting materials for the synthesis of ethyl 3-phenyl-3-oxopropanate. You can draw out the structures on your own to help you answer this question. Premise Response Drag and drop to match 1 Methyl benzoate = A Acetophenone 2 Diethyl carbonate = B Ethyl acetate

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How many molecules in 400g of acetic acid
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Answer:chemical formula of acetic acid is  or

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= 2 × 12 + 4 × 1 + 2 × 16

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so, no of moles of acetic acid = given mass/molecular mass

= 22/60 ≈ 0.367

so, number of moles of acetic acid is 0.367mol

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Explanation:

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3 years ago
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3 years ago
Determine the maximum amount of NaNO3 that was produced during the experiment. Explain how you determine this amount.
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Explanation:

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8 0
2 years ago
Read 2 more answers
Determine the volume, in liters, occupied by 0.015 molecules of oxygen at STp?
Arlecino [84]

5.58 X 10^{-25} Litres is the volume, in liters, occupied by 0.015 molecules of oxygen at STP.

Explanation:

Data given:

molecules of oxygen = 0.015

number of moles of oxygen =?

temperature at STP = 273  K

Pressure at STP = 1 atm

volume = ?

R (gas constant) = 0.08201 L atm/mole K

to convert molecules to moles,

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number of moles = 2.49 x 10^{-26}

Applying the ideal gas law since the oxygen is at STP,

PV = nRT

rearranging the equation:

V = \frac{nRT}{P}

putting the values in the rearranged equation:

V = \frac{2.49 X10^{-26}   X 0.08201 X 273}{1}

V = 5.58 X 10^{-25} Litres.

5 0
3 years ago
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