The answer for the following question is mentioned below.
<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>
Explanation:
Given:
Pressure of gas (P) = 1.2 atm
Volume of a gas (V) = 50.0 liters
Temperature (T) =650 K
To calculate:
no of moles present in the gas (n)
We know;
According to the ideal gas equation;
We know;
<u>P × V = n × R × T
</u>
where,
P represents pressure of the gas
V represents volume of the gas
n represents no of the moles of a gas
R represents the universal gas constant
where the value of R is 0.0821 L atm mole^{-1} K^-1
T represents the temperature of the gas
As we have to calculate the no of moles of the gas;
n = 
n = \frac{1.2*50.0}{0.0821*650}
n = \frac{60}{53.365}
n = 1.12 moles
<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>
.07! you divide 7 by 100%
The answer would most likely be true.
The correct question is
Give the coordination number, the charge of the central metal ion, and select the correct name in each coordination compound:
Na3[CoCl6]
[Ni(CO)4]
[Ni(NH3)3(H2O)2] (NO3)2
Answer:
See explanation for details
Explanation:
Na3[CoCl6]
Name: Sodium hexacholorocobalt III
Charge on the complex: -3
Central metal ion name : cobalt III
coordination number: 6
[Ni(CO)4]
Name: tetracarbonyl nickel (0)
Charge on the complex: 0
Central metal ion name : nickel (0)
coordination number: 4
[Ni(NH3)3(H2O)2] (NO3)2
Name: Diaquatriaminenickel II nitrate
Charge on the complex: +2
Central metal ion name : nickel (+2)
coordination number: 5
Data:
Molar Mass of NaOH = 40 g/mol
Solving: <span>According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
</span>
1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.70*10²² molecules
6.02*10²³y = 0.270*10²³
Solving: <span>Find the mass value now
</span>
40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH
Answer:
The mass is 1.6 grams
