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zepelin [54]
3 years ago
7

Mercury has a mass density of 13.54 g/ml . how many milliliters would 100. grams occupy

Chemistry
1 answer:
frosja888 [35]3 years ago
6 0
<span>7.39 ml For this problem, simply divide the mass of mercury you have by it's density. 100 g / 13.54 g/ml = 7.3855 ml Since we only have 3 significant digits in 100., you need to round the result to 3 significant digits. So 7.3855 ml = 7.39 ml</span>
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How are real gases different from ideal gases?
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Real gases have small attractive and repulsive forces between particles and ideal gases do not. Real gas particles have a volume and ideal gas particles do not. Real gas particles collide inelastically loses energy with collisions and ideal gas particles collide elastically.

3 0
3 years ago
When aqueous solutions of Na2SO4 and Pb(NO3)2 are mixed, PbSO4 precipitates. Calculate the mass of PbSO4 formed when 1.25 L of 0
neonofarm [45]

Answer:

The mass of PbSO4 formed 15.163 gram

Explanation:

mole of Pb(NO₃)₂ = 1.25 x 0.05 = 0.0625

mole of Na₂SO₄ = 2 x 0.025 = 0.05

                                      Pb(NO₃)₂ + Na₂SO₄ → PbSO₄ + 2 NaNO₃

( Mole/Stoichiometry )    \frac{0.0625}{1}           \frac{0.05}{1}

                                     = 0.0625     = 0.05

From  (Mole/ Stoichiometry ) we can conclude that Na₂SO₄ is limiting reagent.

Mass of PbSO₄ precipitate = 0.05 x Molecular mass of PbSO₄

                                            = 0.05 x 303.26 g

                                            = 15.163 g

7 0
3 years ago
1. Un átomo de volframio (W) tiene 74 protones y 108 neutrones. ¿Cuál es su representación adecuada?
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8 0
2 years ago
Using the data in the chart, which of the following would be a correct analysis? x values y values 0 4 1 8 2 16 3 24 The data in
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The data indicates a direct relationship with a positive slope.

<h3>What is direct relationship?</h3>

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6 0
2 years ago
Glacier National Park in Montana is approximately 4,100 ft above sea level with an atmospheric pressure of 681 torr. At what tem
lapo4ka [179]

Answer : The temperature of liquid is, 369.9 K

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of liquid at 373 K = 681 torr

P_2 = vapor pressure of liquid at normal boiling point = 760 torr

T_1 = temperature of liquid = ?

T_2 = normal boiling point of liquid = 373 K

\Delta H_{vap} = heat of vaporization = 40.7 kJ/mole = 40700 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{760torr}{681torr})=\frac{40700J/mole}{8.314J/K.mole}\times (\frac{1}{T_1}-\frac{1}{373K})

T_1=369.907K\approx 369.9K

Hence, the temperature of liquid is, 369.9 K

6 0
3 years ago
Read 2 more answers
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