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olya-2409 [2.1K]
3 years ago
11

Microwave ovens emit microwave energy with a wavelength of 12.7 cm. What is the energy of exactly one photon of this microwave r

adiation?
Physics
1 answer:
Anestetic [448]3 years ago
4 0
Photon energy is the energy carried by a single photon with a certain wavelength and frequency. These terms are related by an equation. 
E = hv
where h is the Planck's constant (6.626 x 10-34<span> J s), v is the frequency which is related to the wavelength by:

</span>λv = c where λ is the wavelength and c is the speed of light (3.00 x 108<span> m/s)
</span>
Therefore, the energy equation 
E = hc / <span>λ
E = </span>(6.626 x 10-34<span> J s)</span>(3.00 x 10^8 m/s) / 0.127 m = 1.565 x 10^-24 J
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5 0
3 years ago
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A possible means for making an airplane invisible to radar is to coat the plane with an antireflective polymer. If radar waves h
Marina CMI [18]

Answer:

The thickness is  t =  0.5615 \ cm    

Explanation:

From the question we are told that

    The wavelength of the of the rader waves is  \lambda =  2.92 \ cm

     The index of refraction of the polymer is  n  = 1.30

The thickness is mathematically represented as

             t =  \frac{\lambda }{4 n }

Substituting values

            t =  \frac{2.92}{4 *  1.30 }

          t =  0.5615 \ cm

6 0
3 years ago
A test of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m.
iris [78.8K]

Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-95^2}{2\times 0.055}\\\Rightarrow a=-82045.45\ km/h^2

Converting to m/s²

a=82045.45=\frac{82045.45\times 1000}{3600\times 3600}=-6.33\ m/s^2

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

\frac{a}{g}=\frac{-6.33}{9.81}=-0.64525\\\Rightarrow a=-0.64525g

Hence, acceleration of the car is -0.64525g

8 0
4 years ago
Which of the following examples describes a situation where a car is experiencing a net force?
Lapatulllka [165]
Where are the options?

8 0
3 years ago
An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit
lora16 [44]

<u>Answer:</u> The velocity of released alpha particle is 1.127\times 10^7m/s

<u>Explanation:</u>

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

m_1v_1=m_2v_2

where,

m_1\text{ and }v_1 = Initial mass and velocity

m_2\text{ and }v_2 = Final mass and velocity

We are given:

m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s

Putting values in above equation, we get:

238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s

Hence, the velocity of released alpha particle is 1.127\times 10^7m/s

4 0
3 years ago
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