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SVETLANKA909090 [29]
3 years ago
6

Draw the alkyne formed when 1,1-dichloro-4-methylpentane is treated with an excess of a strong base such as sodium amide. (give

the neutralized alkyne product, not the acetylide salt.)
Chemistry
1 answer:
alisha [4.7K]3 years ago
4 0
Co2 is correct buddy
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Pls help!!<br>plz answer correctly!<br>will give the brainliest!<br>Urgent!!​
blagie [28]

a)

A: Copper

B: CuO

C: \mathrm{CuSO_4}

D: $\mathrm{CuCO_3}$

E: $\mathrm{CO_2}$

F: $\mathrm{Cu(NO_3)_2}$

b)

$\mathrm{CuO+ H_2SO_4}\rightarrow \mathrm{CuSO_4 + H_2O}$

c)

$\mathrm{CuCO_3+ 2HNO_3}\rightarrow \mathrm{Cu(NO_3)_2+ CO_2+ H_2O}$

7 0
3 years ago
Read 2 more answers
What is hydrogen ion concentration of an acid solution whose PH is 3.4?​
meriva
It’s easy, if the PH of any acidic solution = -Log[H+], where [H+] is hydrogen ion concentration, multiply each term by (-1) then raise each term as a power to (10), so it will become like this:-
[H+] = 10^(-PH)
4 0
3 years ago
) Calculating Heat from Thermochemical Equations
SIZIF [17.4K]

A combustion reaction is a reaction that reacts in the presence of oxygen molecules. Methane will release -3115 kJ/mol of heat.

<h3>What is a combustion reaction?</h3>

A combustion reaction includes the reaction between the chemical reactant and oxygen molecule to produce the product. The combustion reaction between methane and oxygen is given as:

CH₄(g) + 2O₂ (g) → CO₂(g) + 2H₂O (l), ΔH = -890 kJ/mol

The stoichiometry coefficient from the reaction gives 1 mole of methane releases -890 kJ/mol enthalpy.

So, 3.5 moles methane will release = 3.5 × -890 = -3115 kJ/mol

Therefore, -3115 kJ/mol of heat is released.

Learn more about combustion reaction here:

brainly.com/question/27823881

#SPJ1

4 0
2 years ago
You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute b
alexdok [17]

Answer:

             0.045 L  or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

8 0
2 years ago
PLEASE HELP QUICK I WILL GIVE BRAINLIEST
Dvinal [7]

Answer:

3.00 moles Mg

Explanation:

4 0
3 years ago
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