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Cloud [144]
3 years ago
12

Michael is studying the factors that affect corrosion of metals. He wants to test the effect that different concentrations of an

acid will have on the corrosion of a metal. As he sets up and completes his experiment, which of the following experimental designs would be most likely to help him answer his question? A. Allow several metal samples to soak in different amounts of acid of a single concentration and then measure the amount of corrosion on each. B. Prepare solutions of different acid concentrations, measure 50 milliliters of each into different beakers, and place metal samples of different types but of the same mass into the beakers. C. After allowing several small metal sheets to be exposed to different acid concentrations, measure the surface area of each that is corroded. D. After allowing a small metal sheet to be exposed to one acid concentration, place it in different acid concentrations, then measure the surface area that is corroded.
Chemistry
1 answer:
shtirl [24]3 years ago
8 0

Answer:

B. Prepare solutions of different acid concentrations, measure 50 milliliters of each into different beakers, and place metal samples of different types but of the same mass into the beakers.

Explanation:

Since Michael is studying the factors that affect corrosion of metals, and wants to test the effect that different concentrations of an acid will have on the corrosion of a metal, using different acid concentrations of the same volume on different metal samples of the same size would give a much better than all the other options because, a standard volume of acid is used and also a standard mass of metal is used. So, the effect can be measured quantitatively since we have the same quantity of sample.

So, option B is the answer

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1. According to the equation, what mass of hydrogen fluoride is necessary to produce 2.3 g of sodium fluoride?
Luba_88 [7]

Answer:

1.09 grams

Explanation:

According to the following chemical equation:

HF + NaNO₃ -> HNO₃ + NaF

1 mol of hydrogen fluoride (HF) produces 1 mol of sodium fluoride (NaF). Thus, we first convert from mol to grams by using the molar mass (MM) of each compound:

MM(HF)= (1 g/mol x 1 H) + (19 g/mol x 1 F) = 20 g/mol HF

1 mol HF x 19.9 g/mol HF = 20 g

MM(NaF) = (23 g/mol x 1 Na) + (19 g/mol x 1 F) = 42 g/mol NaF

1 mol NaF x 42 g/mol NaF = 42 g

Thus, from 20 g of HF are produced 42 g of NaF  ⇒ 20 g HF/42 g NaF. We multiply this stoichiometric ratio by the mass of NaF produced to calculate the required mass of HF:

20 g HF/42 g NaF x 2.3 g NaF = 1.09 g HF

Therefore, 1.09 grams of HF are necessary to produce 2.3 g of NaF.

5 0
3 years ago
For the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression
Novosadov [1.4K]

Answer:

a. K = [H+][NO2-]/[HNO2]

Explanation:

The computation of the expression of the equilibrium constant is shown below:

Given that the weak acid is HNO_2 that exist in the solution that aqueous

The dissociation equation of HNO_2

HNO_2(aq) \rightarrow NO_{2}^{-} (aq) + H^{+}(aq)

Now

Acidionization constant i.e.

k_a = \frac{[NO_{2}^{-}][H^{+}]}{HNO_{2}}

Therefore the correct option is a.

Hence, the same is to be considered

8 0
3 years ago
Which formula represents an empirical formula<br> O (1) CH,2<br> (2) C, H,<br> (3) CuH<br> O (4) CH
nadezda [96]
The empirical formula for this is 4
8 0
3 years ago
Read 2 more answers
which of the following lewis diagrams best represents the bonding in the N2O molecule, considering formal charges? justify your
avanturin [10]

The best diagram to represent N2O is the second diagram.

The Lewis diagram is used to represent the way two or more atoms bond. This is possible by using lines to represent bonds and dots to represent electrons.

In the case of the molecule N2O bonding occurs in the following way:

  • A triple bond is formed between the nitrogen atoms, which means,  in the Lewis diagram the nitrogen atoms are connected with three lines.
  • The oxygen atom connects to one of the nitrogen atoms.
  • The nitrogen atom that is not connected to the oxygen will have 2 electrons represented by dots because the number of valence electrons is 5, but three were used in the triple bond.
  • The oxygen atom will have 6 electrons represented by dots, which are equal to the number of valence electrons.

Learn more about Lewis diagram in: brainly.com/question/9436176

8 0
3 years ago
PLEASE HELP ME ASAP: Some students are using samples of different substances for a lab investigation. They plan to observe the p
marin [14]

Answer: S,Fe,O2,Sr, and Al

Explanation: I saw it on quizlet

3 0
3 years ago
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