The lab just ran out of 1 M HCl that you need to complete the Benzillic Acid lab. The TA tells you there is 12 M HCl in the fume
hood. You need to make 10.0 mL of 1.0 M HCl. What volume or 12 M HCl will you need to dilute to get the correct volume and concentration of 1.0 M HCl?
1 answer:
Answer:
0.83 mL
Explanation:
Given data
- Initial concentration (C₁): 12 M
- Final concentration (C₂): 1.0 M
- Final volume (V₂): 10.0 mL
We can calculate the initial volume of HCl using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂ / C₁
V₁ = 1.0 M × 10.0 mL / 12 M
V₁ = 0.83 mL
The required volume of the initial solution is 0.83 mL.
You might be interested in
I think the answer is b because that is true
As the number of electrons added to the same principal energy level increases, atomic size generally
C. Decreases.
- methanol image 1
- methanoic acid image 2
Answer:
Explanation:
By Ideal Gas Law, P1*V1 / T1 = P2*V2 / T2
So new pressure = (P1*V1 / T1) / (V2 / T2)
= P1*V1*T2 / T1*V2
= 800*3.6*298 / 250*1.8
= 1907.2 mmHg