Question

Determine how many gmol, kmol, and lbmols there are in 50 kilograms of n-hexane.

Answer 1

Answer: 581 gmol

0.581 kmol

$1.28\times 10^{-3}lbmol$

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{50\times 1000g}{86g/mol}=581mol$

1. The conversion for mol to gmol

1 mol = 1 gmol

581 mol= $\frac{1}{1}\times 581=581gmol$

2. The conversion for mol to kmol

1 mol = 0.001 kmol

581 mol= $\frac{0.001}{1}\times 581=0.581kmol$

3. The conversion for mol to lbmol

1 mol = $2.2\times 10^{-3}lbmol$

581 mol= $\frac{2.2\times 10^{-3}}{1}\times 581=1.28\times 10^{-3}lbmol$