Answer : The molar solubility of
in pure water is, 0.0118 M
Explanation : Given,
![K_{sp}=6.60\times 10^{-6}](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D6.60%5Ctimes%2010%5E%7B-6%7D)
The solubility equilibrium reaction will be:
![PbBr_2\rightleftharpoons Pb^{2+}+2Br^{-}](https://tex.z-dn.net/?f=PbBr_2%5Crightleftharpoons%20Pb%5E%7B2%2B%7D%2B2Br%5E%7B-%7D)
Let the molar solubility be 's'.
The expression for solubility constant for this reaction will be,
![K_{sp}=[Pb^{2+}][Br^{-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BBr%5E%7B-%7D%5D%5E2)
![K_{sp}=(s)\times (2s)^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%28s%29%5Ctimes%20%282s%29%5E2)
Now put all the given values in the above expression, we get:
![6.60\times 10^{-6}=4s^3](https://tex.z-dn.net/?f=6.60%5Ctimes%2010%5E%7B-6%7D%3D4s%5E3)
![s=0.0118M](https://tex.z-dn.net/?f=s%3D0.0118M)
Therefore, the molar solubility of
in pure water is, 0.0118 M
Answer: dry ice is a solid which makes it different from a gas
Explanation:
You have to use the equation q=mcΔT and solve for c to get c=q/mΔT
q=the amount of energy absorbed or released (in this case 150J)
m= the mass of the sample (in this case 10g)
c=the specific heat capacity of the sample
ΔT=the change in temperature (in this case 115°C)
when you plug everything in you should get 0.1304J/g°C
I hope this helps. Let me know if anything is unclear.
Answer:
The valid quantum numbers are l=0, l=-2 and l= 2.
Explanation:
Given that,
n = 3 electron shell
Suppose, the valid quantum numbers are
l = 3
m = 3
l = 0
m = –2
l = –1
m = 2
We know that,
The value of n = 3
Principle quantum number :
Then the principal quantum number is 3. Which is shows the M shell.
So, n = 3
Azimuthal quantum number :
The azimuthal quantum number is l.
![l=0,1,2](https://tex.z-dn.net/?f=l%3D0%2C1%2C2)
Magnetic quantum number :
The magnetic quantum number is
![m=-2,-1,0,1,2](https://tex.z-dn.net/?f=m%3D-2%2C-1%2C0%2C1%2C2)
Hence, The valid quantum numbers are l=0, l=-2 and l= 2.