Answer:
The pressure is 
Explanation:
From the question we are told that
The initial pressure is 
The temperature is 
Let the first volume be
Then the final volume will be 
Generally for a diatomic gas

Here r is the radius of the molecules which is mathematically represented as

Where
are the molar specific heat of a gas at constant pressure and the molar specific heat of a gas at constant volume with values

=> 
=> 
=> ![P_2 = [\frac{1}{2} ]^{\frac{7}{5} } * 11.2](https://tex.z-dn.net/?f=P_2%20%20%3D%20%20%5B%5Cfrac%7B1%7D%7B2%7D%20%5D%5E%7B%5Cfrac%7B7%7D%7B5%7D%20%7D%20%2A%2011.2)
=> 
Answer:
Explanation:
Given
speed of Electron 
final speed of Electron 
distance traveled 
using equation of motion

where v=Final velocity
u=initial velocity
a=acceleration
s=displacement


acceleration is given by 
where q=charge of electron
m=mass of electron
E=electric Field strength

Answer:
because of the idea that like charges get repulsion as a force.
Explanation:
because you wrap the ball with foil, the negative charges will leave the foil and go into the ball by induction. This leaves the foil as a positively charged particle since its electrons left it for the ball, making the ball a negatively charged particle. but if you bring the negative charge near the foil, the electrons will transfer from that and go into the foil, making it negatively charged. Now, because the ball and the foil have the same charge, they repel. the foil flies off.
For the answer to the question above
Forecasting how a business might do in the future.
Calculating tax.
Doing basic payrolls.
Calculating Revenues.
Producing charts.
--Going past 5--
Inventory tracking
Very (VERY) basic CRM for small businesses
I hope my answer helped you.
Answer:
I think the right answer is option B.