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Ede4ka [16]
3 years ago
12

Select the correct answer(s) from the given options:

Mathematics
1 answer:
Olegator [25]3 years ago
5 0

Answer:

A

Step-by-step explanation:

All you have to is multiply 5x20 = 100 and 5 x 10 = 50 Then add and you get 150.

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Is 2/7x proportional on a graph
Dvinal [7]
No it’s proportional on a table doe
7 0
3 years ago
Given the graph, find the initial value of the domain [ ___, 2].
kifflom [539]

According to the graph given, and using it's concept, it is found that the initial value of the domain is of 0.

The <em>domain</em> of a function is the <u>set that contains all possible input values</u>.

  • In a graph, it is <u>represented by the values of x</u>, which is the horizontal axis.

In the graph given in this problem, the function is <u>defined for x between 0 and 2</u>, that is, the <em>domain </em>is [0,2], hence, the initial value of the domain is of 0.

To learn more about domain, you can take a look at brainly.com/question/25897115

4 0
2 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
If you are going somewhere that is 60 miles away and you're going 40 miles per hour the whole time how long will it take you to
Masja [62]
Velocity * time = distance

40 (miles / hour) * t (hours) = 60 (miles)

Take note how the units work. miles/hour * hours = miles. This is an indication that a formula we picked is correct.

Now, looking at our formula (and neglecting units at this point)

40t = 60
t = 60/40
<span>t = 1.5 hours</span>
5 0
3 years ago
How many times is 5 x 10^6 larger than 5 x 10^4
gayaneshka [121]
<h3>Answer:</h3>

By <em>100 times</em>.

Step-by-step explanation:

Each time something is in Scientific Notation, to every power of 10 something is multiplied by, it grows by 10 times.

By knowing that, if both equations use the same starting number, you can minus the notation section from the larger value, to find the answer.

10^6 - 10^4 = 10^2 ---> 100 times.

Hope that helps, :)

3 0
3 years ago
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