1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Angelina_Jolie [31]
3 years ago
3

Fill in the word that completes each statement. Building up electric charges on a Van de Graaff generator is an example of stati

c BLANK . Lightning is an example of static BLANK
Physics
2 answers:
LekaFEV [45]3 years ago
6 0

Answer:

Blank 1. electricity

Blank 2. discharge

Explanation:

The Van de Graaff generator is an electrostatic generator that is based on the principle of electrostatics. The process of the generator is an example of a static charge.

It consists of a belt that is made of insulating material. It is responsible for the accumulation of charges due to its continuous movement inside a hollow metal sphere. So, the number of charges gets to build upon the object.

Hence, building up electric charges on a Van de Graaff generator is an example of static electricity. Lightning is an example of static discharge.

Darya [45]3 years ago
3 0

Answer: The correct answers are electricity and discharge.

Explanation:

Van de Graaff generator is an electrostatic generator. It is used for producing high voltage static electricity. It consists of a hollow metal sphere. The charges is accumulated on it from continuous motion of the belt which is made of an insulating material.

Due to polarization, the charges builds up on an object. Van de Graaf generator is an example of static charge.

Static discharge occurs when the built-up charges flow from the object. Lightning is an example of static discharge. Lightning occurs when the clouds having an opposite charges collide each other.

Therefore, building up electric charges on a Van de Graaff generator is an example of static electricity. Lightening is an example of static discharge.

You might be interested in
A red horse and a black horse raced on a 1-mile long circular racetrack. The red horse
Lyrx [107]

Answer:

Explanation:

B- The red horse's average speed was greater than the black horse's average speed.

Red average speed = 1/120 = 0.00833 mi/s

Black average speed = 1/150 = 0.00667 mi/s

we only know about average speed based on the information given. Either horse could have had higher or lower, even negative,  instantaneous speed during some phase of the race.

5 0
3 years ago
Read 2 more answers
. Set the applied force to Force necessary to Keep the box Moving without accelerating. Restart the animation. Just before the b
Arte-miy333 [17]

Answer:

elative magnitude of the two forces is the same and they are applied in a constant direction.

Explanation:

Newton's second law states that the sum of the forces is equal to the mass times the acceleration  

              ∑ F = m a

in this case there are two forces on the x axis

             F_applied - fr = 0

since they indicate that the velocity is constant, consequently

             F_applied = fr

the relative magnitude of the two forces is the same and they are applied in a constant direction.

3 0
3 years ago
1. A truck of mass 3120 kg is accelerated from rest to a speed of 22.1 m/s. How much work was done on the truck to achieve that
Goryan [66]

Answer:

.5(3120kg)(22.1m/s)^2 = 7.62x10^5 J

Explanation:

8 0
3 years ago
Most applications will ask you to provide all of the following information
Colt1911 [192]

its A chief your welcome




4 0
4 years ago
Read 2 more answers
Add a vector whose magnitude is 13 with angle 27 degrees to one whose magnitude is 11 with angle 45 degrees? Put the length firs
mafiozo [28]

Answer:

Magnitude of the vector is 23.75\ \text{units} and the direction is 35.23^{\circ}

Explanation:

Magnitude of first vector = |A| = 13\ \text{units}

Angle = \theta_1=27^{\circ}

Magnitude of second vector = |B| = 11\ \text{units}

Angle = \theta_2=45^{\circ}

x component of first vector

A_{x}=|A|\cos\theta_1\\\Rightarrow A_x=13\cos27^{\circ}\\\Rightarrow A_x=11.6\ \text{units}

y component of first vector

A_{y}=|A|\sin\theta_1\\\Rightarrow A_y=13\sin27^{\circ}\\\Rightarrow A_y=5.9\ \text{units}

x component of second vector

B_{x}=|B|\cos\theta_2\\\Rightarrow B_x=11\cos45^{\circ}\\\Rightarrow B_x=7.8\ \text{units}

y component of first vector

B_{y}=|B|\sin\theta_2\\\Rightarrow B_y=11\sin45^{\circ}\\\Rightarrow A_y=7.8\ \text{units}

Adding the magnitudes

C_x=A_x+B_x=11.6+7.8\\\Rightarrow C_x=19.4\ \text{units}

C_y=A_y+B_y=5.9+7.8\\\Rightarrow C_y=13.7\ \text{units}

Magnitude of the sum of the vectors would be

|C|=\sqrt{C_x^2+C_y^2}\\\Rightarrow |C|=\sqrt{19.4^2+13.7^2}=23.75\ \text{units}

The direction would be

\theta=\tan^{-1}\dfrac{C_y}{C_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{13.7}{19.4}\\\Rightarrow \theta=35.23^{\circ}

The magnitude of the vector is 23.75\ \text{units} and the direction is 35.23^{\circ}

4 0
3 years ago
Other questions:
  • Fossils are dated using radioactive...<br><br> a. hydrogen <br> b. helium<br> c. carbon
    9·2 answers
  • A 0.015 kg marble moving to the right at 0.225 m/s makes an elastic head-on collision with a 0.030 kg shooter marble moving to t
    10·1 answer
  • All electric devices are required to have identifying plates that specify their electrical characteristics. The plate on a certa
    8·1 answer
  • Have a pH between 0-7.
    6·2 answers
  • What is the freezing point of the substance in the test tube?
    13·1 answer
  • Are active centers of galaxies that radiate powerful x-rays visible across the universe
    10·1 answer
  • Kinetic energy elastic potential energy gravitational potential energy are all forms of what type of energy
    7·1 answer
  • Which statement identifies the chemical property of iron that results in the formation of rust?
    5·1 answer
  • Giving brainly if correct show work​
    10·1 answer
  • Bonds: Including Carbon Compounds Quick Check
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!