Since intermolecular forces is stronger in a solid than a liquid, then NaCl has stronger intermolecular forces than H2O.
Intermolecular forces exists between molecules of the same or different kinds. Water has a dipole moment hence it can interact effectively with the ions in NaCl. This leads to an ion dipole interaction that results in the dissolution of NaCl in H2O.
NaCl is a solid and water is a liquid. Since intermolecular forces is stronger in a solid than a liquid, then NaCl has stronger intermolecular forces than H2O.
Hence, the best argument that compares the intermolecular interactions in water and NaCl is; salt is a solid and water is a liquid, so water has stronger intramolecular forces.
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Answer:
snow storm and a blizzard
Explanation:
Answer:
N=3.05*10^-3g
Explanation:
Using Ln(No/N)=0.693/t½*t
Ln(No/N)=0.693/3*45
No/N=exp(10.396)
100/exp(10.396)=N
100/32695.7=N
N=3.05*10^-3g
If you can provide the reaction you are looking at, then we can provide a more satisfactory answer.
If the forward reaction is exothermic, then reducing the temperature where the reaction occurs will shift the equilibrium towards the right. This is because exothermic reactions release heat, and this will counteract the change as stated in Le Chatelier's Principle.
If the forward reaction is endothermic, then reducing the temperature will shift to the left. This occurs as the backward reaction is the exothermic reaction, and by Le Chatelier's Principle, the reaction will favor the reaction that produces more in to counter a reduction in temperature, in this case the backward direction reaction.
Answer:
Explanation:
Before Hybridization => C: 1s²<u> ⇵</u> 2s²<u>⇵</u> 2p₋₁<u>↑</u> 2p₀<u>↑</u> 2p₊₁<u>∅</u>
After Hybridization => C: 1s² 2sp¹ 2sp¹ 2p₀¹2p₊₁¹ => 2 hybrid orbitals and 2 unhybridized p-orbitals at the n=2 energy level.