Yes, industries releasing heavy metals into land and water ecosystem be penalized.
Heavy metals are defined as the metals with high density in comparison to water, and presumably, linked with toxicity. The sources of heavy metals other industries include mining activities, waste dumps, untreated sewage etc.
Heavy metals are associated with numerous health issues and thus, are considered dangerous. World Health Organization has set limit on Heavy metals in drinking water. The limits are 3.0 milligram/liter for Zinc, 0.010 milligram/liter for Lead, Arsenic, Mercury and 0.003 milligram/liter for Cadmium.
Heavy metals are associated with disorders concerning gastrointestinal tract, respiratory organs, pulmonary organs, liver and brain. Thus, their discharge into water bodies results in direct or indirect consumption via aquatic food, water absorption by plants etc. The waste from industries should be treated before discharging into land or water bodies. Hence, the industries should definitely be penalized, if releasing heavy metals into land and water ecosystem.
Learn more about industrial waste generation and it's treatment-
brainly.com/question/24593837
brainly.com/question/9841649
#SPJ4
Option (C) is the correct answer. In the chemical reaction, reactants are the starting elements or compounds which will chemically react and will form the products. Reactants are only present on the left hand side of the reaction and products are present on the right hand side of the reaction.
Answer:
-2.80 × 10³ kJ/mol
Explanation:
According to the law of conservation of energy, the sum of the heat absorbed by the bomb calorimeter (Qcal) and the heat released by the combustion of the glucose (Qcomb) is zero.
Qcal + Qcomb = 0
Qcomb = - Qcal [1]
We can calculate the heat absorbed by the bomb calorimeter using the following expression.
Qcal = C × ΔT = 4.30 kJ/°C × (29.51°C - 22.71°C) = 29.2 kJ
where,
C: heat capacity of the calorimeter
ΔT: change in the temperature
From [1],
Qcomb = - Qcal = -29.2 kJ
The internal energy change (ΔU), for the combustion of 1.877 g of glucose (MW 180.16 g/mol) is:
ΔU = -29.2 kJ/1.877 g × 180.16 g/mol = -2.80 × 10³ kJ/mol
Answer:
There are
Explanation:
There are 10 elements in CH3CH2COONa.
25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)
<h3>Explanation</h3>
The process:
.
How many moles of this process?
Relative atomic mass from a modern periodic table:
- K: 39.098;
- N: 14.007;
- O: 15.999.
Molar mass of 
:
.
Number of moles of the process = Number of moles of dissolved:
.
What's the enthalpy change of this process?
for 
. By convention, the enthalpy change 
measures the energy change for each mole of a process.
.
The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.
