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nexus9112 [7]
3 years ago
8

An atom that has 13 protons and 15 neutrons is an isotope of what element

Chemistry
2 answers:
Margarita [4]3 years ago
7 0

Answer:

gfs you want to be your friend and rr

Explanation:

DFW area and go work out a plan to me on my

bekas [8.4K]3 years ago
7 0

c. aluminum.............

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Which of the following is a list of the minimum amount of data needed for determining the molar enthalpy of solution of KCl(s) i
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Answer:

 (C) Mass of KCl(s), mass of H20, initial temperature of the water, and final temperature of the solution

Explanation:

molar enthalpy of solution of KCl(s) is heat evolved or absorbed when one mole of KCl is dissolved in water to make pure solution . The heat evolved or absorbed can be calculated by the following relation.

Q = msΔt where m is mass of solution or water , s is specific heat and Δt is change in temperature of water .

So data required is mass of water or solution , initial and final temperature of solution , specific heat of water is known .

Now to know molar heat , we require mass of solute or KCl dissolved to know heat heat absorbed or evolved by dissolution of one mole of solute .

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What is the direction of the polarity of the indicated bond in h3c−oh marked by δ+ and δ−?
Sedbober [7]

Answer:- The direction of the polarity of the indicated bond is from carbon to oxygen.

Explanations:-  There are two types of covalent compounds, polar and non polar. If the bond is between two same atoms for example, H-H, Cl-Cl etc then the bond is non polar. If the bond is between two different atoms then the bond would be polar. The direction of the polarity is from loss electron negative atom to more electron negative atom.

Oxygen is more electron negative than carbon. So, being more electron negative, the bonding electrons are more towards oxygen and it cases partial negative charge on oxygen and partial positive charge on carbon. The direction of the polarity is from less electron negative carbon to more electron negative oxygen.

It is shown in the diagram below:


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