Answer:
1.75 moles of H₂O
Solution:
The Balance Chemical Equation is as follow,
N₂H₄ + O₂ → N₂ + 2 H₂O
Step 1: Calculate the Limiting Reagent,
According to Balance equation,
32.04 g (1 mol) N₂H₄ reacts with = 32 g (1 mol) of O₂
So,
28 g of N₂H₄ will react with = X g of O₂
Solving for X,
X = (28 g × 32 g) ÷ 32.04 g
X = 27.96 g of O₂
It means 29 g of N₂H₄ requires 47.96 g of O₂, while we are provided with 73 g of O₂ which is in excess. Therefore, N₂H₄ is the limiting reagent and will control the yield of products.
Step 2: Calculate moles of Water produced,
According to equation,
32.04 g (1 mol) of N₂H₄ produces = 2 moles of H₂O
So,
28 g of N₂H₄ will produce = X moles of H₂O
Solving for X,
X = (28 g × 2 mol) ÷ 32.04 g
X = 1.75 moles of H₂O
Answer:
8.10 hours.
Explanation:
You start with 500.0g.
After the first half-life, you have 250.0g.
After the second, you have 125.0g.
After the third, you have 62.50g.
Therefore, it takes three half-lives to decay to 62.50g.
Therefore, the elapsed time must be triple the length of one half-life.
24.3
3
=
8.10
, so it is 8.10 hours.
Explanation:
V = m / ρ
<span>V = (23,200/8.96) × 1000 </span>
<span>V = 2,589,285.71 mm³ </span>
<span>Now we have volume and given the radius we can solve for its length. </span>
<span>L = V/πr² </span>
<span>L = (2,589,285.71/(π×1.63²))/1×10^6 </span>
<span>L = 0.31 km </span>
<span>So </span>
<span>R = rL </span>
<span>R = 2.061(0.31) </span>
<span>R = .6389 Ω </span>
<span>End.</span>
Answer:
is
Explanation:
your mixing chemical substances
Answer:
(10 volume exercises) Estoy traduciendo para todos los demás. ¡Que tengas un gran día! :)
Explanation:
