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VladimirAG [237]
3 years ago
7

a length of #8 copper wire (radius = 1.63 mm) has a mass of 24.0 Kg and a resistance of 2.061 Ohm per Km. What is the over all r

esistance of the wire?
Chemistry
2 answers:
lubasha [3.4K]3 years ago
6 0
V = m / ρ 
<span>V = (23,200/8.96) × 1000 </span>
<span>V = 2,589,285.71 mm³ </span>

<span>Now we have volume and given the radius we can solve for its length. </span>
<span>L = V/πr² </span>
<span>L = (2,589,285.71/(π×1.63²))/1×10^6 </span>
<span>L = 0.31 km </span>

<span>So </span>
<span>R = rL </span>
<span>R = 2.061(0.31) </span>
<span>R = .6389 Ω </span>

<span>End.</span>
MatroZZZ [7]3 years ago
6 0

Answer : The overall resistance of the wire is 6.617\times 10^{-4}ohm

Explanation :

First we have to determine the volume of copper wire.

Density of copper wire = 0.00896kg/mm^3

Volume=\frac{Mass }{Density}=\frac{24kg}{0.00896kg/mm^3}=2678.57mm^3

Now we have to determine the area.

Area=\pi r^2

where,

r = radius of copper wire = 1.63 mm

Area=3.14\times (1.63mm)^2=8.343mm^2

Now we have to determine the length of the wire.

\text{Length of the wire}=\frac{\text{Volume of wire}}{\text{Area of wire}}

\text{Length of the wire}=\frac{2678.57mm^3}{8.343mm^2}=321.06mm=3.2106\times 10^{-4}km

conversion used : (1mm=10^{-6}km)

Now we have to determine the overall resistance of the wire.

\text{Overall resistance}=\text{Length of wire}\times \text{Resistance of wire}

\text{Overall resistance}=3.2106\times 10^{-4}km\times 2.061ohm/km

\text{Overall resistance}=6.617\times 10^{-4}ohm

Therefore, the overall resistance of the wire is 6.617\times 10^{-4}ohm

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