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pantera1 [17]
3 years ago
15

Help me please

Physics
2 answers:
vodka [1.7K]3 years ago
7 0
#4 and #9 are true.
#10 is true IF it's an atom of Hydrogen.
The other 7 statements are false.
yarga [219]3 years ago
3 0
1. False
2.False
3.False
4.True
5. True
6. False
7.True
8.False
9. True
10. False

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A ball is thrown horizontally at a speed of 24 meters per second from the top of a cliff. if the ball hits the ground 4.0 second
Viktor [21]

Answer:

78.4 m

Explanation:

To obtain the height of the cliff;

We can use the Relation to obtain the final velocity, v

v = u + at

a = acceleration due to gravity = 9.8m/s²

v = 0 + (9.8*4)

v = 0 + 39.2

v = 39.2 m/s

To obtain the Height, S

v² = u² + 2aS

39.2^2 = 0 + 2(9.8)S

39.2^2 = 0 + 19.6S

1536.64 = 19.6S

S = 1536.64 / 19.6

S = 78.4 m

8 0
2 years ago
A tabletennis ball strikes an at-rest bowling ball. The table tennis ball is
masya89 [10]

-- The table tennis ball bounces back with virtually its entire original speed.

-- The bowling ball rolls forward, so slowly that only complex expensive laboratory equipment can detect and measure its speed.

-- Once again, momentum is conserved !

4 0
3 years ago
Explain whether the unit of work is a fundamental or derived unit
klasskru [66]

Answer:

answer here

Explanation:

the unit of work is fundamental unit because it doesn't depend on other units.

__________________

Thx

6 0
2 years ago
Read 2 more answers
Type the correct answer in the box. Spell the word correctly.
Veronika [31]

Answer:

Vaccination is the procedure by which a person can be immunized against a disease.

6 0
3 years ago
A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.080
deff fn [24]

Answer:

Speed of 0.08 kg mass when it will reach to the bottom position is 1.94 m/s

Explanation:

When rod is released from rest then due to unbalanced torque about the hinge the system will rotate

Now moment of inertia of the system is given as

I = \frac{ML^2}{12} + \frac{m_1L^2}{4} + \frac{m_2L^2}{4}

now we have

M = 0.120 kg

m_1 = 0.02 kg

m_3 = 0.08 kg

now we have

I = \frac{0.120(0.90)^2}{12} + \frac{0.02(0.90)^2}{4} + \frac{0.08(0.90)^2}{4}

so we have

I = 8.1 \times 10^[-3} + 4.05 \times 10^[-3} + 0.0162

I = 0.02835

now by energy conservation we can say work done by gravity must be equal to change in kinetic energy

so we have

\frac{1}{2}I\omega^2 = m_1g \frac{L}{2} - m_2 g\frac{L}{2}

\frac{1}{2}(0.02835)\omega^2 = (0.08 - 0.02)(9.81)(0.45)

\omega = 4.32 rad/s

Now speed of 0.08 kg mass when it reaches to bottom point is given as

v = \omega \frac{L}{2}

v = 4.32 (0.45)

v = 1.94 m/s

3 0
3 years ago
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