Two boys push on a box. They each push to the left with a force of 50 N. At the same time, a third boy pushes on the box, to the
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Answer:
a) 8.83*10⁵ m/s b) 2.80*10⁶ m/s
Explanation:
a) Assuming no other forces acting on the proton, the acceleration on it is produced by the electric field.
By definition, the force due to the electric field is as follows:
F = q*E = e*E (1)
where e is the elementary charge, the charge carried by only one proton, and is e = 1.6*10⁻¹⁹ C.
According to Newton's 2nd law, this force is at the same time, the product of the mass of the proton, times the acceleration a:
F = mp*a (2)
From (1) and(2), being left sides equal, right sides must be equal too:
Solving for a:
⇒ a = 1.3*10¹³ m/s²
As we have the value of a (which is constant due to the field is uniform), the displacement x, and we know that the initial velocity is 0, in order to get the value of the speed, we can use the following kinematic equation:
Replacing by v₀ = 0, a= 1.3*10¹³ m/s² and x = 0.03 m, we can find vf as follows:
⇒ vf = 8.83*10⁵ m/s
b) We can just repeat the equation from above, replacing x=0.03 m by x=0.3 m, as follows:
⇒ vf = 2.80*10⁶ m/s
The final speed of the car at the given conditions is 30.1 m/s.
The given parameters:
- <em>Mass of the car, m = 1700 kg</em>
- <em>Velocity of the car, v = 21 m/s</em>
- <em>Time of motion, t = 10 s</em>
- <em>Additional energy provided by the engine, E₁ = 22,000 J</em>
- <em>Energy used in overcoming friction, E₂ = 3,666.67 J</em>
The change in the energy applied to the car is calculated as;
The final speed of the car is calculated as follows;
Thus, the final speed of the car at the given conditions is 30.1 m/s.
Learn more about change in kinetic energy here: brainly.com/question/6480366