Question 1 of 6
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The spring has been stretched 0.701 m
Explanation:
The elastic potential energy of a spring is the potential energy stored in the spring due to its compression/stretching. It is calculated as
where
k is the spring constant
x is the elongation of the spring with respect to its equilibrium position
For the spring in this problem, we have:
E = 84.08 J (potential energy)
k = 342.25 N/m (spring constant)
Therefore, its elongation is:
Learn more about potential energy:
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Condition for diffraction
Where
a = Distance between slits
m = Order of the fringes
= Wavelength
= At the angle between the ray of light and the projected distance perpendicular between the two objects
For small angles
Where
Where L is the distance between the slits and Y the length of the light.
Replacing we have
The distance between slits d can be expressed also as Where N is the number of the fringes, then
Similarly when there is added a new Fringe we have the change of the distance would be :
Linear distance between fringes is
Therefore the answer is