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ch4aika [34]
4 years ago
9

What is the wavelength of a 256-hertz sound

Physics
1 answer:
Rzqust [24]4 years ago
3 0
Sound at air in STP travels at 343 m/s.

We also know the formula v=f lambda where v is the velocity, f is the frequency and lambda is the wavelength.

Substituting in values to this, we get:

343 = 256 * lambda
lambda = 343/256
=1.34 3sf

Aaand upon doing this, I realise your textbook wants you to assume the speed of sound to be 330m/s, right then, well changing the value to 330, we get 1.29m

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B. Wagon B will accelerate at twice the rate as Wagon A. hope this helps!

6 0
3 years ago
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Can someone help me a bit on this? Will mark brainliest. ( no physical science option soooo)
Advocard [28]

Answer:

When a light wave goes through a slit, it is diffracted, which means the slit opening acts as a new source of waves. How much a light wave diffracts<em> (how much it fans out)</em> depends on the wavelength of the incident light. The wavelength must be larger than the width of the slit for the maximum diffraction. Thus, for a given slit, red light, because it has a longer wavelength, diffracts more than the blue light.

The corresponding relation for diffraction is

d sin(\theta) \approx \lambda,

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From this relation we clearly see that the diffraction angle \theta is directly proportional to the wavelength  \lambda of light—longer the wavelength larger the diffraction angle.

7 0
3 years ago
What is the velocity of an object with a kinetic energy of 800 J and a mass of 12 kg?
Elis [28]

K.E = 1/2 mv²

800 = 1/2 ×12 ×v²

800 =  6 v²

800 / 6  =  v²

=   133.4    =v²

√133.4  =   √v²

11.5   =  v²

I hope this answer is correct.

3 0
3 years ago
Can you please solve this for me urgently want to make sure if my answers are correct?
MA_775_DIABLO [31]

Answer:

<u>Resolving</u><u> </u><u>horizontally</u><u>.</u> :

\sum d_{x} =  - (17.0 \cos 20.0) - (11.0 \cos 35.0) + (30.0 \cos 50.0) + 0 \\  { \underline{d _{x} =  -  5.702 \: m}} \\  \\  \sum d _{y} = (17.0 \sin 20.0) + 12.0 - (11.0  \sin 35.0) - (30.0 \sin 50.0) \\ { \underline{d _{y}  =  - 11.476 \: m}}

therefore, for resultant:

d =  \sqrt{ {d _{y} }^{2} + d _{x}  {}^{2}  }

substitute:

d =  \sqrt{ {( - 5.702)}^{2} +  {( - 11.476)}^{2}  }  \\  \\ d =  \sqrt{164.211}  \\  \\ { \boxed{ \boxed{ \bf{d = 12.8 \: m}}}}

6 0
3 years ago
Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires so
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7 0
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