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Andru [333]
2 years ago
5

If I start driving 80 miles per hour down the interstate how far will I go if I Drive for 4.5 hours

Physics
1 answer:
vodomira [7]2 years ago
4 0
If you are driving 80 miles per hour, you are driving 80 miles for every hour. So if you drive for 4.5 hours, multiply. 80 x 4.5= 360miles

helpful formula:<span>S = V x T

Speed= Velocit</span>y(80mph) x Time(4.5hrs) 
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If you increase the force acting on an object, what will happen to the object's motion
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In its powdered form,the mineral hematite is reddiah which mineral property is best described
Serggg [28]

Answer:

Streak

Explanation:

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Which statement expresses the relationship between the frequency of emitted electrons and the energy they give off?
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Light of wavelength 500nm shines on a pair of slits. This produces an interference pattern on a screen 2.00m behind the slits. M
grandymaker [24]

Answer:

The  value is  d = 0.000125 \  m

Explanation:

From the question we are told that

   The  wavelength is  \lambda  =  500 \  nm =  500 *10^{-9 } \  m

    The  distance is of  the screen is  D =  2.0 \ m

    The  width of the fifth dark spot is y  =  4.00 \  cm  =  0.04 \  m

Generally the width of a fringe is mathematically represented as

           y =  \frac{ n  *  \lambda  *  D }{d }

=>        0.04  =  \frac{ 5  * 500 *10^{-9}  *  2 }{d}

=>        d =  \frac{ 5  * 500 *10^{-9}  *  2 }{0.04}

=>        d = 0.000125 \  m

7 0
3 years ago
An 85-kg hiker climbs to the summit of Mount Mitchell in western North Carolina. During one 2.0-h period, the climber's vertical
Bas_tet [7]

Answer:

The change in gravitational potential energy of the climber-Earth system,\Delta E=4.49\times 10^5\ J

Explanation:

Given that,

Mass of the hiker, m = 85 kg

Time, t = 2 h

Vertical elevation of the climber, h = 540 m

We need to find the change in gravitational potential energy of the climber-Earth system. We know that due to change in position of an object, gravitational potential energy occurs. It is given by :

\Delta E=mgh\\\\\Delta E=85\times 9.8\times 540\\\\\Delta E=4.49\times 10^5\ J

So, the change in gravitational potential energy of the climber-Earth system is 4.49\times 10^5\ J. Hence, this is the required solution.  

5 0
3 years ago
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