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3 years ago

What is the function of physics education

Physics

1 answer:

Fudgin [204]3 years ago

8 0

Answer:

Physics is the natural science that studies matter its fundamental constituents, its motion and behavior through space and time, and the related entities of energy and force

Explanation:

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A 2-column table with 4 rows. The first column labeled substance has entries calcium chloride, calcium bromide, calcium carbonat

yanalaym [24]

Answer:

SAMPLE C

Explanation:

5 0

4 years ago

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The weight of an object on a planet depends not only on its mass, but also on its distance from the planets center. Uranus has m

Ierofanga [76]

The further an object is from the centre of a planet, the lower it's gravitational force. Uranus had 14 times as much mass as earth, but it's also a lot bigger than earth. So assuming an object is on the surface of Uranus, it would be really far away from the centre of Uranus, therefore the gravitational force is less.

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3 years ago

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A box of books weighing 290 N is shoved across the floor of an apartment by a force of 400 N exerted downward at an angle of 34.

NARA [144]

Answer: 1.95s

Explanation:

Given

ma = 290 cos 34.9 - fk

fk = 290 cos 34.9 - ma

fn = mg + 400 sin Φ

fn = 290 + 400 sin 34.9

fn = 290 + 228.9

fn = 518.9

fk = fn * uk

uk = 0.57

290 cos 34.9 - ma = 518.9 * 0.57

290 cos 34.9 - ma = 295.8

290 cos 34.9 - 295.8 = ma

ma = -58

m = 290/10 = 29

a = 58/29

a = 2

Using equation of motion

S = ut + .5at²

3.8 = 0 + .5*2*t²

3.8 = t²

t = 1.95s

3 0

3 years ago

What happens when a wave encounters a boundary and then goes back to the original medium?

lawyer [7]

It causes a movement of convection in the water resulting in a pulling current.

Hope this helpss

7 0

3 years ago

A planet has two small satellites in circular orbits around the planet. the first satellite has a period 18.0 hours and an orbit

puteri [66]

The two satellites orbit around the same planet, so we can use Kepler's third law, which states that the ratio between the cube of the radius of the orbit and the orbital period is constant for the two satellites:
$\frac{r_1^3}{T_1^2}= \frac{r_2^3}{T_2^2}$
where
$r_1$ is the orbital radius of the first satellite
$r_2$ is the orbital radius of the second satellite
$T_1$ is the orbital period of the first satellite
$T_2$ is the orbital period of the second satellite

If we use the data of the problem and we re-arrange the equation, we can calculate the orbital period of the second satellite:
$T_2 = \sqrt{T_1^2 ( \frac{r_2}{r_1} )^3} = \sqrt{(18.0 h)^2 ( \frac{3\cdot 10^7 m}{2 \cdot 10^7 m} )^3} = 33.1 h$

8 0

3 years ago