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Semmy [17]
3 years ago
6

A box (FW = 20 N) is placed on a ramp with a 60° incline. Which of these is an expression for the component of the weight parall

el to the ramp?
A. FW = 20 N × sin60°

B. FW = 20 N × cos60°

C. FW = 20 N × tan60°

D. FW = 20 N
Physics
1 answer:
luda_lava [24]3 years ago
4 0

Answer: A. FW = 20N x sin60°

Explanation: This is because resolution of the forces is taking along the horizontal plane.

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A gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the pressure is increased to 235 kPa?
Dmitrij [34]
For this we want to use Boyle's Law. Boyle’s law states that the pressure and volume of a fixed quantity of a gas are inversely proportional under constant temperature conditions. The formula for this is P1V1 = P2V2. We want to solve this out so it equals V2 (Volume 2). So P1V1 / P2 = V2. Then plug in your values for the variables. So (101)(4.2) / 235 = V2; so 424.2 / 235 = V2. The final volume equals 1.81. I hope this helps, If not I am very sorry.
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How many electrons do hydrogeyn have?
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Among the elements potassium, lithium, and iron, the metallic bonds are likely to be strongest in
Mrac [35]

彼が好きな男のような話は妻と関係があったのでそう

Explanation:これが難しい場合はコメントで教えてくださいが何でも

lol okay

from: a random person :)

4 0
3 years ago
A jet is travelling at a speed of 1200 km/h and drops cargo from a height of 2.5 km above the ground Calculate the time it takes
OLEGan [10]

a) Time of flight: 22.6 s

To calculate the time it takes for the cargo to reach the ground, we just consider the vertical motion of the cargo.

The vertical position at time t is given by

y(t) = h +u_y t - \frac{1}{2}gt^2

where

h = 2.5 km = 2500 m is the initial height

u_y = 0 is the initial vertical velocity of the cargo

g = 9.8 m/s^2 is the acceleration of gravity

The cargo reaches the ground when

y(t) = 0

So substituting it into the equation and solving for t, we find the time of flight of the cargo:

0 = h - \frac{1}{2}gt^2\\t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2500)}{9.8}}=22.6 s

b) 7.5 km

The range travelled by the cargo can be calculated by considering its horizontal motion only. In fact, the horizontal motion is a uniform motion, with constant velocity equal to the initial velocity of the jet:

v_x = 1200 km/h \cdot \frac{1000 m/km}{3600 s/h}=333.3 m/s

So the horizontal distance travelled is

d=v_x t

And if we substitute the time of flight,

t = 22.6 s

We find the range of the cargo:

d=(333.3)(22.6)=7533 m = 7.5 km

7 0
3 years ago
If Anisa swims 85.4 yards in five minutes, how many meters will she swim in 70.0 seconds? ( use the metric system for this quest
Ira Lisetskai [31]

Answer : 18.22 meters

Explanation:

1 yard. = 0.9144 meters

85.4 yards = 78.08976 meters

1 minute = 60 seconds

5 minutes = 300 seconds

Speed of Anisa = distance / time

Speed of Anisa = 78.08976 meters / 300 seconds

Speed of Anisa = 0.26029 meters / second.

Distance travelled in 70 seconds = speed * 70

Distance travelled in 70 seconds = 0.26029 * 70 = 18.22 meters

8 0
3 years ago
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