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3 years ago

Heat the oxygen to about 150 K. What state of matter is this?

Chemistry

1 answer:

adelina 88 [10]3 years ago

3 0

Answer:

Gas

Explanation:

It is easier if you convert the kelvin temperature into Celsius degrees:

ºC = T - 273.15 = 150 - 273.15 = -123.15ºC

Now, you know that that is a very cold temperature. Thus, may be the oxygen is not gas any more but it changed to liquid . . . or solid?

You must search for the boiling point and melting (freezing) point of oxygen in tables or the internet. At standard pressure (about 1 atm) they are:

Melting point: −218.79 °C,

Boiling point: −182.962 °C

That means that:

below -218.79ºC oxygen is solid (not our case).
between -218.79ºC and -182.962ºC oxygen is liquid (not our case)
over -182.962ºC oxygen is a gas. This is our case, because -123.15ºC is a higher temperature than -182.962ºC.

Hence, the state of matter of oxygen at 150K, and standard pressure, is gas.

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4 years ago

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3 years ago

Read 2 more answers

1. At STP, you have 0.101 g of carbon dioxide gas. What is the volume of this gas?

Ber [7]

Answer:

1) A. 0.0515 L

2) B. 35.504 L

3) B. 422.446 g

Explanation:

At STP, you have 0.101 g of carbon dioxide gas. What is the volume of this gas?

Step 1: Data given

Mass of CO2 gas = 0.101 grams

Molar mass of CO2 = 44.01 g/mol

STP = 1 atm and 273K

Step 2: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 0.101 grams / 44.01 g/mol

Moles CO2 = 0.0023 moles

Step 3: Calculate the volume

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Option A is correct

You have 27g of ammonia (nitrogen trihydride) at STP. What is the volume? Hint...you will first need to convert mass of ammonia to moles!

Step 1: Data given

Molar mass of NH3 = 17.03 g/mol

Mass of NH3 = 27.00 grams

STP = 1 atm and 273K

Step 2: Calculate moles NH3

Moles NH3 = 27.00 grams / 17.02 g/mol

Moles NH3 = 1.585 moles

Step 3: Calculate volume

For 1 mol at STP we have 22.4 L

For 1.585 moles we have 22.4 * 1.585 = 35.504 L

Option B is correct

Which of the following represents the MASS of 215 L of dinitrogen monoxide at STP? Hint...find the # of moles of this gas and then use the molar mass to go from moles to mass!

Step 1: Data given

Volume = 215 L

STP = 1 atm and 273 K

Molar mass of N2O = 44.01 g/mol

Step 2: Calulate moles N2O

22.4L = 1 mol at STP

215 L = 215 / 22.4 = 9.60 moles

Step 3: Calculate mass N2O

Mass N2O = moles N2O * molar mass N2O

Mass N2O = 9.60 moles* 44.01 g/mol

Mass N2O = 422.446 g

Option B is correct

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3 years ago

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grandymaker [24]

Answer:

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Explanation:

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The balanced equation is ;

N₂ + 3H₂ → 2NH₃

The mole ratio is the ratio of the coefficients of the combining reactants;

1 mole of N₂ combines with 3 mole of H₂;

So;

$\frac{1 mole of N_{2} }{3 moles of H_{2} }$

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