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Cloud [144]
3 years ago
5

Heat the oxygen to about 150 K. What state of matter is this?

Chemistry
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

  • <u>Gas</u>

Explanation:

It is easier if you convert the kelvin temperature into Celsius degrees:

  • ºC = T - 273.15 = 150 - 273.15 = -123.15ºC

Now, you know that that is a very cold temperature. Thus, may be the oxygen is not gas any more but it changed to liquid . . . or solid?

You must search for the boiling point and melting (freezing) point of oxygen in tables or the internet. At standard pressure (about 1 atm) they are:

  • Melting point: −218.79 °C,
  • Boiling point: −182.962 °C

That means that:

  • below -218.79ºC oxygen is solid (not our case).
  • between -218.79ºC and -182.962ºC oxygen is liquid (not our case)
  • over -182.962ºC oxygen is a gas. This is our case, because -123.15ºC is a higher temperature than -182.962ºC.

Hence, <em>the state of matter of oxygen at 150K</em>, and standard pressure, is gas.

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boyakko [2]

Answer:

straight line down then left and right that should be it

Explanation:

7 0
3 years ago
calculate density of a rectangular solid, which has a mass of 25.71 g. It is 2.30 cm long, 4.01 cm wide and 1.82 cm high.
Levart [38]
Density is a property of the substances that is obtained by dividing its mass by the volume. For a rectangular solid, the volume may be solved by the following equation,
 
                                          V = L x W x H

Substituting the given values for the dimension,
 
                  V = (2.30 cm) x (4.01 cm) x (1.82 cm) = 16.78786 cm³

Calculating for the density,
 
                                Density = mass / volume
 
                Density = 25.71 cm / <span>16.78786 cm³ = 1.53 grams per cm</span>³

Thus, the density of the given solid is approximately 1.53 grams per cm³.




5 0
3 years ago
A cup of gold colored metal beads was measured to have a mass 425 grams. By water displacement, the volume of the beads was calc
Troyanec [42]

Given parameters;

Mass of gold colored metal beads  = 425g

Volume of water displaced by beads = 48.0cm³

Unknown;

Identity of the metal = ?

Given densities;

Gold: 19.3 g/mL

Copper: 8.86 g/mL

Bronze: 9.87 g/mL

Density is an intensive property of any substance. This implies that we can use the density of any substance to identify it.

Density can be defined as the mass per unit volume of a substance. Every substance has a unique mass per volume.

 Mathematically;

                    Density  = \frac{mass}{volume}

where mass is in kg or g

           volume is in  m³ or cm³

To find the density, we must know the mass and volume.

In this problem, the volume of the gold metal beads is the same as the volume of water displaced. This is a way to measure volume of solids.

Since the volume is given in cm³, and we are comparing with choices that have units in g/mL, we simply convert the volume in cm³ to mL

                   1cm³  = 1mL³

So therefore, volume of gold colored metal is 48mL

Now input the parameters given and solve for the density;

           Density  = \frac{425g}{48mL }    = 8.85g/mL

From the given densities, we clearly see that copper is the metal since they both of similar densities.

4 0
3 years ago
Which of these salts has the highest pH? K2SO4 Cu2SO4 NH4Cl NaCH3COO
OLEGan [10]

the answer is D.  just took the test

7 0
4 years ago
Read 2 more answers
Draw the principal organic product expected when 2-methylthiophene reacts with hno3. show minimized formal charges, if applicabl
qaws [65]

Answer:

2-Methyl-5-nitrothiophene  

Explanation:

The 2- and 5-positions of thiophene are the most susceptible to electrophilic aromatic substitution.

Thus, the major product from the reaction of 2-methylthiophene with HNO₃ in acetic acid is 2-methyl-5-nitrothiophene.

5 0
3 years ago
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