Answer:
VH2SO4 = 145.3 mL
Explanation:
Mw BaO2 = 169.33 g/mol
⇒ mol BaO2 = 53.5g * ( mol BaO2 / 169.33 g BaO2) = 0.545 mol BaO2
⇒according to the reaction:
mol BaO2 = mol H2SO4 = 0.545 mol
⇒ V H2SO4 = 0.545 mol H2SO4 * ( L H2SO4 / 3.75 mol H2SO4 )
⇒V H2SO4 = 0.1453 L (145.3 mL)
Electronic configuration of Rb: 2.8.8.8.8.3
Valence electron is 3....
M C C O R M I C K T E A M ’ S O P E N Q U A N T U M M AT E R I A L S D ATA B A S E
O F F E R S U N L I M I T E D A C C E S S T O
ANALYSES OF NEARLY 300,000 COMPOUNDS
Answer:
See the attached image
Explanation:
The first step is the production of the <u>carboanion</u> in the
compound. We will get the <u>negative charge</u> on the methyl group and the <u>positive charge</u> in the Li atom.
Then the carboanion can <u>attack the acetone</u>. The double bond of the oxo group would <u>delocalized</u> upon the oxygen, generating a positive charge in the carbon that can be attacked by the carboanion formaiting a <u>new C-C bond</u>.