Answer:
290 grams
Explanation:
Let's begin by writing the balanced chemical equations:
Then we calculate the number of moles in 97g of propane.
n(propane)=
According to the balanced chemical equation, one mole of propane produces 3 moles of carbon dioxide. So the available number of moles of propane must be multiplied by three to work out the number of carbon dioxide produced.
n(carbon dioxide)= 2.1995mol*3 = 6.5985mol
mass(carbon dioxide) = moles * molar mass
= 6.5985 mol * 44.01 g/mol
= 290 grams
Option B is correct
K = Kp /Kr
The given equation indicating, the product containing 6 moles of proton whereas the reactant contains 2 mole of bismuth and 3 mole of hydrogen sulphide.
Hence, in reaction B there are 2 mole of bismuth and 3 mole of hydrogen sulphide reacting to produce 6 moles of proton. whereas the concentration of Bi2S3 is not considered as it is present in solid phase.
Variables we know:
t = 8 seconds
Vi = 0 m/s
g = -9.81
Δy = ?
Vf = ?
Equation we will be using to solve for Vf: Vf = Vi + gt
Steps to solve:
Vf = (0) + (-9.81)(8)
Vf = -78.48 m/s
Hope this helps!! :)
Answer:
Do research on a Particular topic
