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Juli2301 [7.4K]
4 years ago
12

A student is playing with a radio-controlled race car on the balcony of a sixth-floor apartment. An accidental

Physics
1 answer:
pentagon [3]4 years ago
8 0

Answer:

No, it is independent

Explanation:

As we know that car is moving horizontally

so the vertical component of the speed is zero initially

so in order to hit the ground we know that

\Delta y = v_y t + \frac{1}{2}at^2

so here we know that

h = 0 + \frac{1}{2}gt^2

on solving above equation for time

t = \sqrt{\frac{2h}{g}}

so we will say that it will not depends on the initial horizontal speed

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What are the only elements that exist in nature as isolated atoms
agasfer [191]

Answer:

The only such elements are the Noble Gases (He, Ne, Ar, Kr, Xe, Rn)

(that is helium, neon, argon, krypton, xenon and radon)

Term: Monoatomic

Explanation:

6 0
3 years ago
Which graph below represents how the velocity of the sphere changes over time when falling with constant acceleration?
Amiraneli [1.4K]

Graph B represents the velocity of the sphere changes over time when falling with constant acceleration.

  • Acceleration is the measure of how quickly a body's velocity varies with regard to time, and constant acceleration occurs when a body's velocity changes proportionately over a period of time, or at a constant rate. It measures in m/s2.
  • It is claimed that a body has continual positive acceleration when it begins to move with an initial velocity of zero and gradually increases to a positive value over time.
  • Constant positive acceleration is demonstrated by a ball falling freely in a vertical direction.

To know more about  constant acceleration. visit : brainly.com/question/9754169

#SPJ1

4 0
1 year ago
A two-slit pattern is viewed on a screen 1.26 m from the slits. If the two fourth-order maxima are 53.6 cm apart, what is the to
Anettt [7]

Answer:

= 6.55cm

Explanation:

Given that,

distance = 1.26 m

distance between  two fourth-order maxima = 53.6 cm

distance between central bright fringe and fourth order maxima

y = Y / 2

  =  53.6cm / 2

  = 26.8 cm

  =0.268 m

tan θ = y / d

         = 0.268 m /  1.26 m

         = 0.2127

       θ = 12°

4th maxima

d sinθ = 4λ

d / λ = 4 / sinθ

d / λ = 4 / sin 12°

d / λ = 19.239

for first (minimum)

d sinθ = λ / 2

sinθ =  λ / 2d

       =  1 / 2(19.239)

       = 1 / 38.478

       = 0.02599

    θ =  1.489°

tan θ = y / d

y = d tan θ

  = 1.26 tan 1.489°

  = 0.03275

the total width of the central bright fringe  

Y = 2y

  = 2(0.03275)

  = 0.0655m

  = 6.55cm

4 0
3 years ago
For question #13, use the following picture: 13. The picture is a model of a nitrogen atom. What is incorrect about the atomic o
valentinak56 [21]

the electrons should be in the outer valence levels/shells.

8 0
3 years ago
suppose the same chest is at rest. you push it horizontally with force of 110N but it does not budge. What is the contact force
Radda [10]

Answer:

110 N

Explanation:

When a force is applied on a body and body does not move, it means the body remains at rest.

In this condition, there is a contact force between the body and the floor which is called static friction.

Th static friction force is a self adjusting force and comes into play when the body is at rest.

Here, the applied force is 110 N and the chest is not moving, that means a static friction force is acting between the chest and the floor. This static friction force is the force of contact between the chest and the floor. The static friction force is equal to the applied force when the body does not move.

So, the contact force between the chest and the floor is 100 N.

4 0
3 years ago
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