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Doss [256]
3 years ago
5

After working in a fast-food restaurant for three years to pay for your college tuition, you vowed never to work in a restaurant

again. But after graduation the only job offer you receive is a managerial job at a local restaurant. Your acceptance of this job may result in __________ dissonance.
Physics
1 answer:
devlian [24]3 years ago
4 0

Answer:

The correct answer is Cognitive.

Explanation:

The psychologist Leon Festinger proposed the theory of cognitive dissonance, which explains how people try to maintain their internal consistency. He suggested that individuals have a strong inner need that pushes them to ensure that their beliefs, attitudes and behavior are consistent with each other. When there is inconsistency between them, the conflict leads to a lack of harmony, something that people strive to avoid.

This theory has been widely studied in the field of psychology and can be defined as the discomfort, tension or anxiety that individuals experience when their beliefs or attitudes conflict with what they do. This displeasure can lead to an attempt to change behavior or defend their beliefs or attitudes (even reaching self-deception) to reduce the discomfort they produce.

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What’s the answer for this
AlladinOne [14]

Answer:

52.5 m

Explanation:

The displacement is the area under the velocity vs time graph.

From 0 to 5 seconds, the area is the area of the triangle plus the area of the rectangle.

x = ½ (3 s) (15 m/s) + (2 s) (15 m/s)

x = 52.5 m

8 0
3 years ago
Read 2 more answers
When a fork is placed in a hot piece of lasagna, thermal energy is transferred up the fork by
kirill [66]
<span>fast-moving particles colliding with slow-moving particles</span>
6 0
3 years ago
Read 2 more answers
A bat hits a moving baseball. If the bat delivers a net eastward impulse of 0.80 N-s and the ball starts with an initial horizon
AURORKA [14]

Answer:

0.084 kg

Explanation:

I = 0.80 N-s (East wards) = 0.80 i N-s

u = 3.8 m/s = - 3.8 i m/s

v = 5.7 m/s = 5.7 i m/s

Let m be the mass of bat.

I = m (v - u)

0.8 i = m ( 5.7 i + 3.8 i)

0.8 i = m x 9.5 i

m = 0.084 kg

8 0
3 years ago
I would like to know why this is the correct answer
Helen [10]

The acceleration of the object if the net force is decreased = 0.13 m/s²

<h3>Further explanation</h3>

Given

A net force of 0.8 N acting on a 1.5-kg mass.

The net force is decreased to 0.2 N

Required

The acceleration of the object if the net force is decreased

Solution

Newton's 2nd law :

\tt \sum F=m.a

The mass used in state 1 and 2 remains the same, at 1.5 kg

  • state 1

ΣF=0.8 N

m=1.5 kg

The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.8}{1.5}\\\\a=0.53`m/s^2

  • state 2

ΣF=0.2 N

m=1.5 kg

The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.2}{1.5}\\\\a=0.13~m/s^2

8 0
3 years ago
Use the work—energy theorem to solve each of these problems. You can use Newton's laws to check your answers. Neglect air resist
andreyandreev [35.5K]

Answer:

a) It is moving at 43.15\frac{m}{s^{2}} when reaches the ground.

b) It is moving at 101.44\frac{m}{s^{2}} when reaches the ground.

Explanation:

Work energy theorem states that the total work on a body is equal its change in kinetic energy, this is:

W=K_f-K_i (1)

with W the total work, Ki the initial kinetic energy and Kf the final kinetic energy. Kinetic energy is defined as:

K=\frac{mv^2}{2} (2)

with m the mass and v the velocity.

Using (2) on (1):

W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2} (3)

In both cases the total work while the objects are in the air is the work gravity field does on them. Work is force times the displacement, so in our case is weight (w=mg) of the object times displacement (d):

W=Fd=wd=mgd (4)

Using (4) on (3):

mgd=\frac{mv_f^2}{2}-\frac{mv_i^2}{2} (5)

That's the equation we're going to use on a) and b).

a) Because the branch started form rest initial velocity (vi) is equal zero, using this and solving (5) for final velocity:

v_f=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*95}

v_f=43.15\frac{m}{s^{2}}

b) In this case the final velocity of the boulder is instantly zero when it reaches its maximum height, another important thing to note is that in this case work is negative because weight is opposing boulder movement, so we should use -mgd:

-mgd=-\frac{mv_i^2}{2}

Solving for initial velocity (when the boulder left the volcano):

v_i=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*525}

v_i=101.44 \frac{m}{s^{2}}

3 0
3 years ago
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