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Marrrta [24]
3 years ago
11

If sodium has one valence electron and sulfur has six, how many sodium atoms are needed to form an ionic bond with sulfur?

Physics
2 answers:
Luden [163]3 years ago
6 0

Answer: two

Explanation:

Nesterboy [21]3 years ago
5 0

Answer:

Its 2

Explanation:

This compound has a central Sulfur atom surrounded by 4 Oxygens in a covalent bonds, with an overall charge of negative 2 and 2 Sodium atoms with a charge of positive one. Thus making the answer 2.

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Modern wind turbines are larger than they appear, and despite their apparently lazy motion, the speed of the blades tips can be
Crank

Answer:

(a) v = 65.35 m/s

(b) ac = 82.16 m/s²

Explanation:

Kinematic of the blades of the wind turbine

The blades of the wind turbine describe circular motion and the formulas that apply to this movement are as follows:

v = ω * R   Formula (1)

Where:

v : tangential velocity (m/s)

ω : angular velocity (rad/s)

R : radius of the particle path (m)

The velocity vector is tangent at each point to the trajectory and its direction is that of movement. This implies that the movement has centripetal acceleration (ac):

ac =  ω²* R Formula (1)

ac : centripetal acceleration (m/s²)

Data:

ω=  12 rpm = 12 rev/min

1 rev = 2π rad

1 min = 60 s

ω=  12 rev/min = 12 (2π rad)/(60 s)

ω = 1.257 rad/s

R = 52 m

(a)Tangential velocity at the tip of a blade (v)

We apply the formula (1)

v =  ω* R

v =  ( 1.257)* (52) = 65.35 m/s

(a)  Centripetal acceleration at the tip of a blade (ac)

We apply the formula (2)

ac =  ω²*R

ac =   ( 1.257)²* (52) = 82.16 m/s²

6 0
2 years ago
A toy car attached to a rope is traveling around in a circle. It makes 4 laps in 12s.What is the angular velocity of the toy car
umka21 [38]

Answer:

2.09 rad/s

Explanation:

Given that,

A toy car makes 4 laps in 12 s.

We need to find the angular velocity of the toy car. We need to find the angular velocity of the toy car.

4 laps = 25.13 rad

So,

v=\dfrac{25.13\ rad}{12\ s}\\\\v=2.09\ rad/s

So, the angular velocity of the toy car is 2.09 rad/s.

3 0
3 years ago
A gymnast is in a tucked position to complete her somersaults. While tucked her moment of inertia about an axis through the cent
torisob [31]

Answer:

\omega_s=12.8886\ rad.s^{-1}

Explanation:

Given that:

  • moment of inertia of tucked body, I_t=16\ kg.m^2
  • rotational speed of the body, N_t=2.5\ rev.s^{-1}
  • i.e. \omega_t=2\pi\times 2.5=15.708\ rad.s^{-1}
  • moment of inertia of  the straightened body, I_s=19.5\ kg.m^2

<u>Now using the law of conservation of angular momentum:</u>

angular momentum of tucked body=angular momentum of straight body

I_t.\omega_t=I_s.\omega_s

16\times 15.708=19.5\times \omega_s

\omega_s=12.8886\ rad.s^{-1}

8 0
3 years ago
Can someone answer these and show work please??
Nataliya [291]
3. n=1.31. So using Snell's Law of Refraction, n1sinθ=n2sinθ. Your second theta should be 15 degrees instead. The angle is ALWAYS from the vertical. Since n of air is just 1, n2=(sin45)/(sin15)=1.31.

4. This is a bit interesting, the way YOU set this up. Because I am a physicist, the dashed line for refracting angles should be perpendicular to the object's surface. Whether that is how you are told by your instructor, or your own doing, I digress. Anyway, Snell's Law again, n1sinθ=n2sinθ. N of air is 1 at an angle of 90 degrees. So 1=sin90 for both shapes. Your angle for the triangular prism is 55 degrees, so n=1/sin(55). For the funky looking shape, your angle should actually be 90-35. ANGLE IS TO THE DASHED LINE, NOT THE SURFACE. So this n is 1/sin(55) again.

You got this
8 0
2 years ago
What is the planet's rotational speed from slowest to fastest?​
larisa86 [58]

Answer:

Jupiter is the fastest whereas Venus is the slowest

5 0
1 year ago
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