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3 years ago

If sodium has one valence electron and sulfur has six, how many sodium atoms are needed to form an ionic bond with sulfur?

Physics

2 answers:

Luden [163]3 years ago

6 0

Answer: two

Explanation:

Nesterboy [21]3 years ago

5 0

Answer:

Its 2

Explanation:

This compound has a central Sulfur atom surrounded by 4 Oxygens in a covalent bonds, with an overall charge of negative 2 and 2 Sodium atoms with a charge of positive one. Thus making the answer 2.

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When a monochromatic light of wavelength 433 nm incident on a double slit of slit separation 6 µm, there are 5 interference frin

Bad White [126]

Answer:

The number of interference fringes is $n = 3$

Explanation:

From the question we are told that

The wavelength is $\lambda = 433 \ nm = 433 *10^{-9} \ m$

The distance of separation is $d = 6 \mu m = 6 *10^{-6} \ m$

The order of maxima is m = 5

The condition for constructive interference is

$d sin \theta = n \lambda$

=> $\theta = sin^{-1} [\frac{5 * 433 *10^{-9}}{ 6 *10^{-6}} ]$

=> $\theta = 21.16^o$

So at

$\lambda_1 = 632.9 nm = 632.9*10^{-9} \ m$

$6 * 10^{-6} * sin (21.16) = n * 632.9 *10^{-9}$

=> $n = 3$

4 0

3 years ago

What is the variable that is manipulated by the experimenter during an experiment called

larisa [96]

Independent variable
The independent variable is the variable that is controlled and manipulated by the experimenter. For example, in an experiment on the impact of sleep deprivation on test performance, sleep deprivation would be the independent variable.

3 0

3 years ago

About when was the sail developed, making travel possible on the open water?

dalvyx [7]

The first sail was developed in 1300 BC in Mesopotamia

4 0

3 years ago

The orbital radius of the Earth (from Earth to Sun) is 1.496 x 10^11 m.

mrs_skeptik [129]

Explanation:

The orbital radius of the Earth is $r_1=1.496\times 10^{11}\ m$

The orbital radius of the Mercury is $r_2=5.79 \times 10^{10}\ m$

The orbital radius of the Pluto is $r_3=5.91 \times 10^{12}\ m$

We need to find the time required for light to travel from the Sun to each of the three planets.

(a) For Sun -Earth,

Kepler's third law :

$T_1^2=\dfrac{4\pi ^2}{GM}r_1^3$

M is mass of sun, $M=1.989\times 10^{30}\ kg$

So,

$T_1^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 1.496\times 10^{11}\\\\T_1=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times1.496\times10^{11}}\\\\T_1=2\times 10^{-4}\ s$

(b) For Sun -Mercury,

$T_2^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.79 \times 10^{10}\ m\\\\T_2=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.79 \times 10^{10}}\ m\\\\T_2=1.31\times 10^{-4}\ s$

$T_3^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.91 \times 10^{12}\\\\T_3=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.91 \times 10^{12}}\\\\T_3=1.32\times 10^{-3}\ s$

8 0

3 years ago

a balloon inflated in a room at 297k has a volume of 4.00 l. the balloon is then heated to a temperature of 331 k. what is the n

Naddika [18.5K]

V2 = 4.4579 L

Since pressure is constant, use Charle’s law.
Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

V(olume) 1 = V(olume) 2
————— —————
T(emperature) 1 T(emperature)2

4.00 L = V2
———- ———
297 K 331 K

Cross multiply
(4.00 L x 331 K) = (297 K x V2)
Simplify
1324 L/K = 297 K x V2
Isolate V2 by dividing out 297 K
1324 L/K = V2
————
297 K
(This cancels out the kelvin and leaves you with Liters as the volume measure)

V2 = 4.4579 L

Round to significant digits if required

7 0

2 years ago